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Someone purchase something online, cost is $5 (process fee

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Someone purchase something online, cost is $5 (process fee [#permalink]

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New post 04 Jun 2009, 10:43
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Someone purchase something online, cost is $5 (process fee for once purchase) plus $19.8 for each. How many articles did he purchase?
1). Total cost is 190
2). Total cost is more than 188 and less than 208
Manager
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Re: ds [#permalink]

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New post 04 Jun 2009, 10:56
Quote:
Someone purchase something online, cost is $5 (process fee for once purchase) plus $19.8 for each. How many articles did he purchase?
1). Total cost is 190
2). Total cost is more than 188 and less than 208


1.Total cost 190
19.8x9=178.2+5=183.2
not suff

2.Total cost is more than 188 and less than 208
19.8x10=198+5=203

203 is b/w 188 and 208
Hence B
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Re: ds [#permalink]

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New post 04 Jun 2009, 12:35
Someone purchase something online, cost is $5 (process fee for once purchase) plus $19.8 for each. How many articles did he purchase?
1). Total cost is 190
2). Total cost is more than 188 and less than 208

Let \(X\) represent the number of articles that were purchased.

\(C = 19.8X + 5\)

(1) \(C = 190\)

2 Equation, 2 variables \(\longrightarrow SUFFICIENT\).

(2) \(188 < C < 208\)

\(188 < 19.8X + 5 < 208\)

\(183 < 19.8X < 203\)

\(1830 < 198X < 2030\)

\(9 \frac{8}{33} < X < 10 \frac{25}{99}\)

\(\longrightarrow X = 10\)

\(\longrightarrow SUFFICIENT\).

Final Answer, \(D\).
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Re: ds [#permalink]

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New post 04 Jun 2009, 13:14
Someone purchase something online, cost is $5 (process fee for once purchase) plus $19.8 for each. How many articles did he purchase?
1). Total cost is 190

C= (x-1)*19.8+5
C=190

SUFFICIENT

2). Total cost is more than 188 and less than 208

208<[(x-1)*19.8+5]>188
2030/198+1<[x]>1830/198+1
9.xxxx <x<10.xxxx
since x is the nuber of items , it will be integer only.
x=10

SUFFICIENT
IMO D
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Re: ds [#permalink]

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New post 04 Jun 2009, 18:33
Quote:
Someone purchase something online, cost is $5 (process fee for once purchase) plus $19.8 for each. How many articles did he purchase?
1). Total cost is 190

C= (x-1)*19.8+5
C=190


Could you tell me how you got (x-1) and how the sum equal to 190$?
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Re: ds [#permalink]

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New post 09 Jun 2009, 01:50
Agree with Hades, D
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Re: ds [#permalink]

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New post 10 Jun 2009, 01:58
I have a doubt here..

should we assume that all the articles are brought through single online purchase.
though that makes life easy, is the assumption supposed to be assumed ? [:)]
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Re: ds [#permalink]

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New post 15 Jun 2009, 12:20
Based on the way the question was written (a bit loose - "someone purchase", "once", "$19.8"), I think it's fair to assume vcbabu paraphrased the question a bit. It's possible that the original wording of the question made it clear there was only 1 order.

I doubt it was intended as a "trick you by making you assume" - type of question.

I do agree that if the question was clearer, it'd be easier to answer. (I had to read it over a couple times)
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Re: ds [#permalink]

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New post 15 Jun 2009, 20:55
vcbabu wrote:
Someone purchase something online, cost is $5 (process fee for once purchase) plus $19.8 for each. How many articles did he purchase?

1). Total cost is 190
2). Total cost is more than 188 and less than 208


The question is flawed because 190 cannot be equal to the cost of no/none/any number of purchses.

1. Total cost = 190. This amount is not equal to the purchse cost of no number of articles however it is close to the costs of 9 articles. It should be suff because 190 cannot be equal to the costs of neither 10 articles nor 8 articles no matter how they are purchased. So the number of articles purchased has to be 9.

It should be sufff though is flawed.


2. This looks suff but actually not because there are 2 possibilities:

i. 188 < 19.8n + 5 < 208 for n is 10
or 188 < 203 < 208

ii. 188 < [(19.8n + 5) + (19.8m+5)] < 208 for n = 5 and m = 4 (there could be more number of online purchases but the number of articles purchased cannot be smaller than 9)

or 188 < 188.2 < 208.
So there could be 9 or 10 articles purchased. This is not suff.

The correct answer would be A if statement 1 were not flawed.


Quote:
\(188 < 19.8X + 5 < 208\)
This is not the only equation possible.

\(188 < 19.8X + 5 + 5 < 208\) is also possible.
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Re: ds [#permalink]

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New post 16 Jun 2009, 01:17
answer has to be (B), since with option (A) we cannot reach to a specific number of articles.

what is given in the OA???
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Re: ds [#permalink]

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New post 24 Jun 2009, 14:30
Does anyone know the OA for this question?

I originally picked D, but was bugged by the same thoughts that a lot of the people who picked B.

I think the question is poorly written if it leaves room for so much speculation, or I might be missing some minor detail...
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Re: ds [#permalink]

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New post 30 Jun 2009, 19:59
answer should be B as there is no way we can achieve a total of 190 or the question is flawed. OA pls.
Re: ds   [#permalink] 30 Jun 2009, 19:59
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