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alphonsa
Joined: 22 Jul 2014
Last visit: 25 Oct 2020
Posts: 106
Given Kudos: 197
Concentration: General Management, Finance
Schools: Cox '19 (D) Babson '19 (A$) Katz '19 (D) Eller"19 (A$) Northeastern '19 (A$) Krannert '19 (A$) ISB '18 (D) Rutgers '19 (A) Olin '19 (I)
GMAT 1: 670 Q48 V34
WE:Engineering (Energy)
Products:
Schools: Cox '19 (D) Babson '19 (A$) Katz '19 (D) Eller"19 (A$) Northeastern '19 (A$) Krannert '19 (A$) ISB '18 (D) Rutgers '19 (A) Olin '19 (I)
GMAT 1: 670 Q48 V34
Posts: 106
09 Sep 2014, 23:05
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B
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Difficulty:
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58% (01:18) correct
42%
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wrong
based on 277
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Steve spent a total of $36 on transportation for 3 days. What was his median expenditure?
(1) On day 3, he spent $8
(2) On day 1, he spent $12.
Source: 4Gmat
(1) On day 3, he spent $8
(2) On day 1, he spent $12.
Source: 4Gmat
09 Sep 2014, 23:45
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alphonsa
Statement 1 alone is not sufficient.
Statement 2: On day 1, he spent $12.
Total $36 for 3 days.
If on one day he spent $12, he must have spent 36 - 12 = 24 on other two days together. In how many ways can you split 24 into two?
Either both numbers could be equal to 12 each (which is half of 24) or one will be less than 12 and the other will be greater than 12. In either case, when you write all 3 numbers in ascending order, 12 will be in the middle.
e.g. 24 = 12+12
3 day spending -> 12, 12, 12
or
24 = 2 + 22
3 day spending -> 2, 12, 22
and so on...
In all cases, 12 will be in the middle and hence will be the median.
Answer (B)
KanishkM
Joined: 09 Mar 2018
Last visit: 18 Dec 2021
Posts: 755
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Given Kudos: 123
Location: India
Schools: DeGroote'21 Desautels '21 NUS '21
14 Feb 2019, 20:09
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alphonsa
From 1 Money spent on day 3 is given,
Now the expenditure for 3 days can be 19,9,8 or 20,8,8
We will get different values for median
from 2, day 1 he spent 12, again we have to look for some numbers in which he had spent the money
12,10,14
12,12,12
9,12,25
In all these cases, we are getting 12 as the median value
B
