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Marshall & McDonough Moderator
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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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12 Jan 2017, 23:05
St1: k = 13t + 13 t = 0 > k is prime t = any other integer > k is not prime Not Sufficient
St2: k = 17! + 13 > 13(Some number + 1) > k is not prime Sufficient
Answer: B



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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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13 Jan 2017, 01:13
If x,y,z are positive integers,is the product x*y*z divisibly by 21? (1) The greatest common factor of x, y, and z is 3. (2) The lowest common multiple of x, y, and z is 63.Source> SelfMade
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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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13 Jan 2017, 03:25
If a positive integer \(n\) is given by \(n=26*p\) where \(p\) is a prime number greater than 2,how many even divisors does n have ?
A)4 B)3 C)2 D)1 E)cannot be determined.Source> SelfMade
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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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13 Jan 2017, 05:47
Here is what i did in this Question. We are asked about the number of factors of a Positive integer N.
Statement 1> The only way 27*N^3 =3^3*N^3 will have 16 factors is if N is a prime number. Hence N must be a prime number => 2 factors only. Hence Sufficient.
Statement 2> Since N is an integer => N^3 must be a perfect Cube. The only perfect cube between 90 and 200 is 125. Hence N^3 must be 125 => N must be 5 => Two factors only. Hence sufficient.
Hence D.
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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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13 Jan 2017, 05:55
If \(N\) is a positive integer,what is the value of \(N\)? (1) \(N\) is divisible by 31. (2) \(\frac{N}{100}\) is a prime number.
Source> SelfMade
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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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13 Jan 2017, 07:43
stonecold wrote: If a positive integer \(n\) is given by \(n=26*p\) where \(p\) is a prime number greater than 2,how many even divisors does n have ?
A)4 B)3 C)2 D)1 E)cannot be determined.
Source> SelfMade n=26p =2*13*p where p is odd(prime >2 is odd) thus no. of even factors are 2 , 2*13 , 2*p , 2*13*p =4 Ans A



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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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13 Jan 2017, 07:47
rohit8865 wrote: stonecold wrote: If a positive integer \(n\) is given by \(n=26*p\) where \(p\) is a prime number greater than 2,how many even divisors does n have ?
A)4 B)3 C)2 D)1 E)cannot be determined.
Source> SelfMade n=26p =2*13*p where p is odd(prime >2 is odd) thus no. of even factors are 2 , 2*13 , 2*p , 2*13*p =4 Ans A Counter Question> What if p=13?
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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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13 Jan 2017, 08:04
stonecold wrote: rohit8865 wrote: stonecold wrote: If a positive integer \(n\) is given by \(n=26*p\) where \(p\) is a prime number greater than 2,how many even divisors does n have ?
A)4 B)3 C)2 D)1 E)cannot be determined.
Source> SelfMade n=26p =2*13*p where p is odd(prime >2 is odd) thus no. of even factors are 2 , 2*13 , 2*p , 2*13*p =4 Ans A Counter Question> What if p=13?
sure p may be 13 then this is debatable one on my side it will better be a DS question



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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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13 Jan 2017, 08:19
rohit8865 wrote: stonecold wrote: rohit8865 wrote: Counter Question> What if p=13?
sure p may be 13 then this is debatable one on my side it will better be a DS question We may not agree on that. Since two values of the number of factors are possible => The answer cannot be determined. Hence E.
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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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13 Jan 2017, 08:26
stonecold wrote: sure p may be 13 then this is debatable one on my side it will better be a DS question
[/quote] We may not agree on that. Since two values of the number of factors are possible => The answer cannot be determined. Hence E.[/quote] well i have not considered the last option Ans will be E



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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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13 Jan 2017, 08:29
A number is said to be prime saturated if the product of all the different positive prime factors of n is less than the square root of n. If p is a prime saturated,what is the value of p? A)p is a perfect cube. B)2≤p≤15Source> SelfMade
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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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13 Jan 2017, 08:31
stonecold wrote: If \(N\) is a positive integer,what is the value of \(N\)? (1) \(N\) is divisible by 31. (2) \(\frac{N}{100}\) is a prime number.
Source>SelfMade (1) n could be 31 or 62 not suff (2) n can be 200 or 300 not suff combining n=31p from (1) & 31p/100 is prime From (2) thus n must be 3100 Ans C



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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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13 Jan 2017, 08:55
St1: x = y = z = 3 > x * y * z is not divisible by 3*7 x = 3, y = z = 21 > x * y * z is divisible by 3*7 Not Sufficient.
St2: LCM(x, y, z) = 63 x * y * z is a multiple of 63 and hence divisible by 21 Sufficient.
Answer: B



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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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13 Jan 2017, 09:17
stonecold wrote: A number is said to be prime saturated if the product of all the different positive prime factors of n is less than the square root of n. If p is a prime saturated,what is the value of p?
A)p is a perfect cube. B)2≤p≤15
Source> SelfMade A) \(p\) is a perfect cube. Then \(p\) could be \(3^3=27\) or \(2^3=8\). Insufficient. B) \(2 \leq p \leq 15\) First, \(p\) can't be a prime. Out 2, 3, 5, 7, 11, 13, left 4, 6, 8, 9, 10, 12, 14, 15 Second, \(p\) can't be in prime factorization of \(a \times b\) where \(a\) and \(b\) are prime. Out 6, 10, 14, 15. Left 4, 8, 9, 12. Third, \(p\) can't be in form of \(a^2\) where \(a\) is prime. Out 4, 9. Left 8, 12. 8 is a cube, so 8 is prime saturated. \(12=2^2 \times 3\). We have \(2 \times 3 = 6 > \sqrt{12}=2\sqrt{3}\) so 12 is not prime saturated. Hence, \(p=8\). Sufficient. The answer is B.
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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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13 Jan 2017, 10:33
If \(a = b^3*c^2*d\),how many positive factors does a have?
(1)\(b\), \(c\) and \(d\) are prime numbers. (2)\(b\),\(c\),\(d\) are distinct integers.
Source> SelfMade
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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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14 Jan 2017, 05:07
stonecold wrote: If \(a = b^3*c^2*d\),how many positive factors does a have?
(1)\(b\), \(c\) and \(d\) are prime numbers. (2)\(b\),\(c\),\(d\) are distinct integers.
Source>SelfMade Clearly, the answer is A



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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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14 Jan 2017, 09:18
If \(x\) is an integer, is \(x^3\) divisible by 7 ? (1) \(x^{12}\) is divisible by 7. (2) \(x^4\) is divisible by 7.
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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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14 Jan 2017, 11:11
stonecold wrote: How many positive even divisors does 96 have ?
A. 12 B. 10 C. 8 D. 6 E. Cannot be determined 96= 2^5*3 thus no. of even factors = 5*2=10 Ans B



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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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15 Jan 2017, 14:17
Mock Test 1(600700) Updated. stonecoldsmocktest217160.html#p1676182
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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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16 Jan 2017, 11:51
Mock Test 2 (700+) Updated. stonecoldsmocktest217160.html#p1676182
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Re: STONECOLD'S MATH CHALLENGE  PS AND DS QUESTION COLLECTION.
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