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Bunuel
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My approach is the following:

We need the greatest prime number, so we have to maximize x-2y, how? y has to be negative

So then:

\(x^{2}<9^{2}\) ---> x = 9
\(y^{2}<(-5)^{2}\) ---> y = -5

Limit = 9 + 10 = 19 prime but we can't take it, we need a prime less than 19

If we take one digit less we have that:

\(x^{2}=8^{2}\) ---> x = 8
\(y^{2}=(-4)^{2}\) ---> y = -4

So then 8 + 8 =16 not prime

There are two numbers between 16 and 19 --> 17 (prime) and 18 (not prime)

Answer E
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selim
If \(x^2\) < 81 and \(y^2\) < 25 what is the largest prime number that can be equal to x-2y ?

A) 3
B) 7
C) 11
D) 13
E) 17

Algebraic approach -

\(x^2<81 => -9<x<9\) --------(1)

\(y^2<25=> -5<y<5\), multiply this equation by \(-2\) to get

\(-10<-2y<10\) -----(2). Add equation (1) & (2) to get

\(-19<x-2y<19\). In this range the Largest Prime Number is \(17\).

Option E
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selim
If \(x^2\) < 81 and \(y^2\) < 25 what is the largest prime number that can be equal to x-2y ?

A) 3
B) 7
C) 11
D) 13
E) 17


\(x^2<81.......|x|<9.........x>-9...and...x<9\)
\(y^2<25.......|y|<5.........y>-5.... and.... y<5\).....

the MAX value of x-2y is when x is positive and y is negative
so just LESS than 9-2*(-5)=9+10=19 so <19
therefore x-2y can take ANY value <19...
17 is the closest prime number to 19, hence answer 17


E
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x<9
y<5

For number to be largest
x-2y

we need to have x has +ve and y should be -ve

9-2(-5) = 19
but it should be less than 19

so 9-2(-4) = 17
answer E
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Bunuel: Is the fact that we are not dealing with integers the reason that we don't have to do this additional step: -8<=x<=8 and -8<= -2y<=8?

Bunuel
selim
If x^2<81 and y^2<25, what is the largest prime number that can be equal to x-2y?

A) 3
B) 7
C) 11
D) 13
E) 17

This is my own question and below is official solution:



10. If x^2<81 and y^2<25, what is the largest prime number that can be equal to x-2y?
A. 7
B. 11
C. 13
D. 17
E. 19

Notice that we are not told that \(x\) and \(y\) are integers.

\(x^2<81\) means that \(-9<x<9\) and \(y^2<25\) means that \(-5<y<5\). Now, since the largest value of \(x\) is almost 9 and the largest value of \(-2y\) is almost 10 (for example if \(y=-4.9\)), then the largest value of \(x-2y\) is almost 9+10=19, so the actual value is less than 19, which means that the largest prime that can be equal to \(x-2y\) is 17. For example: \(x=8\) and \(y=-4.5\).

Answer: D.
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SergejK
Bunuel: Is the fact that we are not dealing with integers the reason that we don't have to do this additional step: -8<=x<=8 and -8<= -2y<=8?

Bunuel
selim
If x^2<81 and y^2<25, what is the largest prime number that can be equal to x-2y?

A) 3
B) 7
C) 11
D) 13
E) 17

This is my own question and below is official solution:



10. If x^2<81 and y^2<25, what is the largest prime number that can be equal to x-2y?
A. 7
B. 11
C. 13
D. 17
E. 19

Notice that we are not told that \(x\) and \(y\) are integers.

\(x^2<81\) means that \(-9<x<9\) and \(y^2<25\) means that \(-5<y<5\). Now, since the largest value of \(x\) is almost 9 and the largest value of \(-2y\) is almost 10 (for example if \(y=-4.9\)), then the largest value of \(x-2y\) is almost 9+10=19, so the actual value is less than 19, which means that the largest prime that can be equal to \(x-2y\) is 17. For example: \(x=8\) and \(y=-4.5\).

Answer: D.
______________________________
Yes.
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If x^2 < 81 and y^2 < 25, what is the largest prime that can be equal to x – 2y?
A. 7
B. 11
C. 13
D. 17
E. 19

Correct Answer: D (17)
Common Trap Answers: E(19) & C(13)

The Traps:

1. Strict Inequalities Are Misinterpreted

The given constraints are:
x^2 < 81 → so -9 < x < 9
y^2 < 25 → so -5 < y < 5


Many test-takers mistakenly treat these as inclusive (i.e., ≤) and assume values like x=9 or y=−5 are valid.
But since the inequalities are strict (“<”), boundary values like 9 or -5 are not allowed.
Hence, a value like x−2y=19 is not possible, even though many pick it, thinking it is.

This is a classic GMAT trap — misreading strict vs. inclusive inequalities leads to incorrect range assumptions.

2. Students Assume Integer-Only Values

Even if students understand the bounds, they often test only integer values of x and y.
For example:
x = 8, y = -4 → x - 2y = 8 + 8 = 16, and then incorrectly pick 13 as the highest prime < 16. So they pick option C.


But this ignores that x and y can be real numbers (e.g., x=8,y=−4.5), and 17 is valid.


This is another layer of the trap: assuming integers when not required.

Range Analysis:

To better understand, try testing extremes:

xyx - 2y
-9-5-9 + 10 = 1
-95-9 - 10 = -19
9-59 + 10 = 19 ❌ (not allowed)
959 - 10 = -1


So, valid x – 2y values are in (-19, 19) → 17 is possible and is the highest prime in this range.

Key Takeaways:

  • Don’t assume variables are integers unless explicitly stated
  • Strict inequalities (< or >) exclude boundary values
  • Use upper/lower bound logic or a table to test ranges
  • Be alert to trap answers derived from integer assumptions or inclusive boundaries
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