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Only in one group = x
Students common = y

x = 20 + 20 + 20 - 2(y) + 3(5)
x = 60 + 15 -2(y) = 75 - 2y

So values should satisfy the equation

x = 75 - 2y
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Hi melaos.,

Check out the below link for clarification

https://gmatclub.com/forum/advanced-over ... 44260.html

melaos
MacFauz
Only in one group = x
Students common = y

x = 20 + 20 + 20 - 2(y) + 3(5)
x = 60 + 15 -2(y) = 75 - 2y

So values should satisfy the equation

x = 75 - 2y

don't quite understand how you get the numbers.

can pls elaborate?

Had a chance to look at the link -- -which formula are you using ?

Total=A+B+C−(sum of 2−group overlaps)+(all three)+NeitherTotal=A+B+C−(sum of 2−group overlaps)+(all three)+Neither.

OR

Total=A+B+C−(sum of EXACTLY 2−group overlaps)−2∗(all three)+NeitherTotal=A+B+C−(sum of EXACTLY 2−group overlaps)−2∗(all three)+Neither.
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Hi,

I don't get the same answer.

I get :
- 7 students chose one discipline only in each class
- 9 students for each pair of classes (with 4 students with 2 disciplines and 5 students with 3 disciplines)
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sir correct answer must be exactly1=33, exactly2=6, which is not provided in the choices
since number of students in Chem+Phy+Bio=Exactly1+2*Exactly2+3* Exactly3
60=e1+2*e2+3*5
e1+2*e2=45
e1=33 & e2=7 satisfies the condition.
Please guide me I m incorrect
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pappal
sir correct answer must be exactly1=33, exactly2=6, which is not provided in the choices
since number of students in Chem+Phy+Bio=Exactly1+2*Exactly2+3* Exactly3
60=e1+2*e2+3*5
e1+2*e2=45
e1=33 & e2=7 satisfies the condition.
Please guide me I m incorrect
­You are looking at Exactly one and common to any pair, and not exactly one and exactly 2.

 
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Can someone please clearly explain this question using venn diagram?

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Appreciable guidance

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The question says each class has 20 students, and among these classes there are students in common, thus the total students are less than 60.

with previously given answers, if total students with only 1 class is 33 and students with only 2 classes is 7 then for any class, total students will be (33/3)+7+7+5 = 30, which does not satisfy the 20 student per class criteria.

The answer is, 2 students common between only 2 class, and total 33 students with only one class: here total students in a class is (33/3)+2+2+5=20.
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