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Re: Tara drove at an average speed of 50 miles per hour for the first 50 [#permalink]
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sashiim20 wrote:
Tara drove at an average speed of 50 miles per hour for the first 50 miles of her trip and then at an average speed of 75 miles per hour for the remaining 50 miles of her trip. If she made no stops during the trip, what was Tara's average speed, in miles per hour, for the entire trip?

(A) 50
(B) 55
(C) 60
(D) 65
(E) 70


Either use the total distance/ total time concept

or the Average speed eqn =2V1V2/V1+V2.

So 2*50*75/(50+75)= 60
Ans:C
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Re: Tara drove at an average speed of 50 miles per hour for the first 50 [#permalink]
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sashiim20 wrote:
Tara drove at an average speed of 50 miles per hour for the first 50 miles of her trip and then at an average speed of 75 miles per hour for the remaining 50 miles of her trip. If she made no stops during the trip, what was Tara's average speed, in miles per hour, for the entire trip?

(A) 50
(B) 55
(C) 60
(D) 65
(E) 70


We can use the following formula:

average speed = (distance 1 + distance 2)/(time 1 + time 2)

We see that time 1 = 1 hour, time 2 = 50/75 = 2/3 hours, and distance 1 = distance 2 = 50 miles. Thus:

average = (50 + 50 )/(1 + 2/3)

average = 100/(5/3) = 300/5 = 60 mph.

Answer: C
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Re: Tara drove at an average speed of 50 miles per hour for the first 50 [#permalink]
In such cases just take the harmonic mean (HM).

HM of A and B = 2 (A*B)/(A+B).
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Re: Tara drove at an average speed of 50 miles per hour for the first 50 [#permalink]
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Re: Tara drove at an average speed of 50 miles per hour for the first 50 [#permalink]
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