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Total Students = TS = 160
Students who choose Chemistry = C = 110
Students who choose Physics = P = 70
Students who choose Other = Ot = 15 (minimum)
Students who choose Neither = N = 0 (as it is a mandate to choose atleast one subject)
Students who choose Chemistry & Physics = P&C = ?

Maximum Students who could have chosen P&C
We need to see the minimum number of students who choose one of the two subjects. As that will be the maximum number of students who can choose both Chemistry & Physics.
So, it will be 70

Maximum Students who could have chosen P&C = 70

Minimum Students who could have chosen P&C
We have to assume that the Ot, 15 is maximum possible (will be explained below).

TS = C + P + Ot - C&P + N
160 = 110 + 70 + Ot - C&P + 0
C&P = 180 + Ot - 160
C&P = 20 + Ot (to minimize C&P Ot has to be minimized (as the value of Ot will increase the value of C&P will also increase. SO C&P will not be minimun in that case). In this case the minimum value of Ot can be 15.

[b]So, C&P = 20 + 15 = 35[/b]

Maximum = 70
Minimum = 35
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Solution :
Attachment:
IR Q1 Solution.png
IR Q1 Solution.png [ 32.65 KiB | Viewed 9417 times ]

minimum possible number of students who choose to take both chemistry and physics from table 2 in attachment is 35

maximum possible number of students who choose to take both chemistry and physics from table 3 in attachment is 70
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Given, Venn diagram,
n(c)= 110, n(p)=70, neither n or p >=15

We know that, n(cUp)= n(c) + n(p)- n(c⋂p)

For minimum n(c⋂p), when both sets are not overlapping or minimum overlapping
So, neither n or p= minimum value = 15, n(cUp) = 160-15 = 145, but we have n(c)= 110, so, only n(p)=35 required and, n(c⋂p) =35

For maximum n(c⋂p), when both sets are 100% overlapping or maximum overlapping
So, n(c⋂p) = n(p)= 70
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Hello Everyone!

This is a hard overlapping sets questions, everyone got it correct. OA is:

Minimum possible number of students who take both: 35
Maximum possible number of students who take both: 70

Excellent work done by Sumi1010 and Deepakjhamb

OE will be posted soon.

Thank you
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