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The afternoon before a popular amusement park opens for the season, Sh
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23 Apr 2015, 02:41
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61% (02:27) correct 39% (03:36) wrong based on 107 sessions
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The afternoon before a popular amusement park opens for the season, Shirley has a pass that will let her ride each ride continuously without waiting in line. For each of the four most popular rides, the ride will run for an allotted time, then stop to change passengers (in negligible time) and start again. The Sea Serpent runs every 15 minutes starting at 10am. The Wild Mouse runs every 30 minutes starting at 11am. The Raptor runs every 40 minutes starting at noon. And the Mantis runs every 45 minutes starting at 11am. Each ride runs continuously and stops only to let its passengers off and immediately begin again. If Shirley is able to get on her first ride starting at 2:00pm and wants to ride all four rides, but needs 10 minutes between rides to move from one to the next, what is the earliest time she could finish riding all four rides? A. 4:15pm B. 4:30pm C. 4:45pm D. 5:00pm E. 5:15pm Kudos for a correct solution.
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Re: The afternoon before a popular amusement park opens for the season, Sh
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23 Apr 2015, 04:04
Hi, IMO it should be C that is 4:45pm Started at 2pm with the widl mouse , ended at 2:30pm. took 10 mins break = 2:40pm @ 2:40pm she rode the raptor which ended at 3:20pm , took 10 mins break = 3:30pm @3:30pm she rode the mantis which ended at 4:15pm, took 10 mins break = 4:25pm @ 4:30pm only she could ride sea serpent which will end at 4:45pm. Hence C Regards Celestial. Kudos if it a correct solution Bunuel wrote: The afternoon before a popular amusement park opens for the season, Shirley has a pass that will let her ride each ride continuously without waiting in line. For each of the four most popular rides, the ride will run for an allotted time, then stop to change passengers (in negligible time) and start again. The Sea Serpent runs every 15 minutes starting at 10am. The Wild Mouse runs every 30 minutes starting at 11am. The Raptor runs every 40 minutes starting at noon. And the Mantis runs every 45 minutes starting at 11am. Each ride runs continuously and stops only to let its passengers off and immediately begin again. If Shirley is able to get on her first ride starting at 2:00pm and wants to ride all four rides, but needs 10 minutes between rides to move from one to the next, what is the earliest time she could finish riding all four rides?
A. 4:15pm B. 4:30pm C. 4:45pm D. 5:00pm E. 5:15pm
Kudos for a correct solution.



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Re: The afternoon before a popular amusement park opens for the season, Sh
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23 Apr 2015, 09:07
Hi, C for me as below. First the 45 mins ride, then 30 min, ride, 40 min ride, and finally 15 min ride. Bunuel wrote: The afternoon before a popular amusement park opens for the season, Shirley has a pass that will let her ride each ride continuously without waiting in line. For each of the four most popular rides, the ride will run for an allotted time, then stop to change passengers (in negligible time) and start again. The Sea Serpent runs every 15 minutes starting at 10am. The Wild Mouse runs every 30 minutes starting at 11am. The Raptor runs every 40 minutes starting at noon. And the Mantis runs every 45 minutes starting at 11am. Each ride runs continuously and stops only to let its passengers off and immediately begin again. If Shirley is able to get on her first ride starting at 2:00pm and wants to ride all four rides, but needs 10 minutes between rides to move from one to the next, what is the earliest time she could finish riding all four rides?
A. 4:15pm B. 4:30pm C. 4:45pm D. 5:00pm E. 5:15pm
Kudos for a correct solution.
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Re: The afternoon before a popular amusement park opens for the season, Sh
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23 Apr 2015, 19:44
solved it ... answer is C .. but took 5 mints any shortcut on this ?
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Re: The afternoon before a popular amusement park opens for the season, Sh
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23 Apr 2015, 20:43
adityadon wrote: solved it ... answer is C .. but took 5 mints any shortcut on this ? It does require you to find the ride timing pattern but thereafter, it takes a few secs only. She enters at 2 so jot down the timings from 2 onwards: SS  2:00, 2:15, 2:30, 2:45, 3:00, 3:15 (ignore 10, 10:15, 10:30 etc) WM  2:00, 2:30, 3:00, 3:30, 4:00, 4:30 (ignore 11, 11:30...etc) Rap  2:00, 2:40, 3:20, 4:00, 4:40, (ignore 12, 12:40, 1:20 though you need to review them in mind to know at what time the first ride runs at or after 2) Man  2:00, 2:45, 3:30, 4:15, 5:00 (ignore 11, 11:45, 12:30, 1:15) Now look for exact 10 min intervals between the rides to take minimum time. Look at the highlighted spots: WM from 2 to 2:30, Rap from 2:40 to 3:20 and Man from 3:30 to 4:15. Now you are left with SS which you can start at 4:30 (15 min break) and get done by 4:45. Note that you took 5 mins more than the minimum time you could have taken riding each ride with 10 mins breaks. Looking at the options, you see that 4:45 is there and the earlier option is 4:30. There is no way you could have been done by 4:30 since you took only 5 mins more than the minimum. Hence (C) must be the answer.
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The afternoon before a popular amusement park opens for the season, Sh
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23 Apr 2015, 21:39
Bunuel wrote: The afternoon before a popular amusement park opens for the season, Shirley has a pass that will let her ride each ride continuously without waiting in line. For each of the four most popular rides, the ride will run for an allotted time, then stop to change passengers (in negligible time) and start again. The Sea Serpent runs every 15 minutes starting at 10am. The Wild Mouse runs every 30 minutes starting at 11am. The Raptor runs every 40 minutes starting at noon. And the Mantis runs every 45 minutes starting at 11am. Each ride runs continuously and stops only to let its passengers off and immediately begin again. If Shirley is able to get on her first ride starting at 2:00pm and wants to ride all four rides, but needs 10 minutes between rides to move from one to the next, what is the earliest time she could finish riding all four rides?
A. 4:15pm B. 4:30pm C. 4:45pm D. 5:00pm E. 5:15pm
Kudos for a correct solution. First thing to note is that all the rides will be in ready to board state at 2PM . how ? sea serpent @10am + 15*4*4mins = 2PM Wild mouse @11am + 30*2*3mins = 2PM Raptor @12PM + 40*3 = 2PM Manits @11AM + 45*4= 2PM now i see these four numbers and quickly identified that we have to start with wild mouse as i will get 30,40,45 all in series with 10min gap. 15, 30 , 40 , 45 30(wild mouse) +10(min wait) =40(raptor 40*1) 30+10(wait)+40+10(wait) =90(Mantis 45*2) 30+10(wait)+40+10(wait)+45+10(wait)=145 as 15*10=150 so she has to wait for another 5 mins so finally the the total time taken is 30+10(wait)+40+10(wait)+45+10(wait)+5(min)+15 = 165mins . 2PM + 165mins = 4PM + 45Mins answer C
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The afternoon before a popular amusement park opens for the season, Sh
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27 Apr 2015, 01:29
Bunuel wrote: The afternoon before a popular amusement park opens for the season, Shirley has a pass that will let her ride each ride continuously without waiting in line. For each of the four most popular rides, the ride will run for an allotted time, then stop to change passengers (in negligible time) and start again. The Sea Serpent runs every 15 minutes starting at 10am. The Wild Mouse runs every 30 minutes starting at 11am. The Raptor runs every 40 minutes starting at noon. And the Mantis runs every 45 minutes starting at 11am. Each ride runs continuously and stops only to let its passengers off and immediately begin again. If Shirley is able to get on her first ride starting at 2:00pm and wants to ride all four rides, but needs 10 minutes between rides to move from one to the next, what is the earliest time she could finish riding all four rides?
A. 4:15pm B. 4:30pm C. 4:45pm D. 5:00pm E. 5:15pm
Kudos for a correct solution. VERITAS PREP OFFICIAL SOLUTION:The good news is that all four rides will begin exactly at 2pm, so you have a common starting point to begin mapping out her afternoon. Also noteworthy is that only one ride (the 40minute Raptor) has a duration that’s not a multiple of 15, meaning that fitting in the Raptor will be interesting. One way to minimize the amount of time, then, is to look at which other numbers (15, 30, and 45) will, with a 10minute break after, end in a 40 or 20. That allows you to start with the 30minute ride from 2pm to 2:30, then take the mandatory 10 minute break, and immediately get on the 2:40 ride for the 40minute event. That takes you to 3:20, and a 10minute break gets you to exactly 3:30, when any of the remaining two (the 45minute ride and the 15minute ride) will be leaving. If you then take the 45minute ride, that will take you to 4:15, at which point you need one more 10minute break to get to 4:25. Now is your first “deadweight” piece of time, a 5minute rest until 4:30 when you can take the 15minute ride and be done at 4:45. With a time of 4:45 already achieved, D and E are eliminated. And since there were only 5 “wasted” (not riding, not walking from ride to ride in a 10minute break) minutes, there clearly isn’t a way to shave down to 4:30. Therefore you can confidently pick C, the correct answer.
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Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
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Re: The afternoon before a popular amusement park opens for the season, Sh
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