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For given n numbers, their average = (their sum)/n OR average/Sum = 1/n
So if we are asked that average is what % of sum, we have to find
Average/Sum * 100 = 1/n * 100

So if we can get n, we can get the answer. Statement 2 gives us the value of n, but statement 1 does not.

Hence B answer
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Bunuel
The average (arithmetic mean) of a list of positive numbers is what percent of the sum of the numbers?

(1) The sum of the numbers in the list is 150.
(2) There are 25 numbers in the list.


Average as a percentage of the sum of the numbers = Average of Number *100 / Sum of the numbers

Average as a percentage of the sum of the numbers = (Sum of Number/Count of Numbers) *100 / Sum of the numbers


Average as a percentage of the sum of the numbers = 100/Count of Numbers)

Statement 1: NOT SUFFICIENT

Statement 2: SUFFICIENT

Answer: option B
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Bunuel
The average (arithmetic mean) of a list of positive numbers is what percent of the sum of the numbers?

(1) The sum of the numbers in the list is 150.
(2) There are 25 numbers in the list.

Par of GMAT CLUB'S New Year's Quantitative Challenge Set

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Bunuel
The average (arithmetic mean) of a list of positive numbers is what percent of the sum of the numbers?

(1) The sum of the numbers in the list is 150.
(2) There are 25 numbers in the list.

Tricky question. I was definitely fooled, but indeed the correct answer is B. The sum cancels out so it doesn't matter what the value is.

Avg * # of terms = sum

Avg = \(\frac{Sum}{terms}\)

\(\frac{sum}{25} = [fraction]x% * sum[/fraction]\)

x = 4%
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Bunuel
The average (arithmetic mean) of a list of positive numbers is what percent of the sum of the numbers?

(1) The sum of the numbers in the list is 150.
(2) There are 25 numbers in the list.

Asked: The average (arithmetic mean) of a list of positive numbers is what percent of the sum of the numbers?

Average = Sum of numbers / Count of numbers
Average/Sum of numbers = 1/Count of numbers = (100/Count of numbers) %

(1) The sum of the numbers in the list is 150.
Since average is unknown
NOT SUFFICIENT

(2) There are 25 numbers in the list.
Count of numbers = 25
Average/Sum of numbers = 1/Count of numbers = (100/Count of numbers) % = 4%
SUFFICIENT

IMO B
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