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The compensation of person A is a fixed salary of $3,000 plus $30 for each additional computer sold after the first 40. The compensation of person B is straightaway $60 per computer sold. For a sale of how many computers each is the compensation of A 25% more than that of B?
A. 30
B. 40
C. 50
D. 60
E. 70
A. 30
B. 40
C. 50
D. 60
E. 70
08 Apr 2026, 22:26
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A = 3000 + (n-40)*30 ; n= no of computer sold.
B = n * 60
What is n such that the compensation of A 25% more than that of B
ie., 3000 + (n-40)*30 = 1.25 * 60 * n
Solve for n we get, n=40.
Option B
B = n * 60
What is n such that the compensation of A 25% more than that of B
ie., 3000 + (n-40)*30 = 1.25 * 60 * n
Solve for n we get, n=40.
Option B
09 Apr 2026, 09:00
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Check with options:
Since we have 60 per computer for B take a multiple leading to 3000 to compare with A.
Take 50 first and check.
We find that B=3000 and A=3300.
They are pretty close together and we need to widen this gap. How?
Take the next lesser number of items = 40 so that B doesn't catch up A by as much as just 300 difference.
With 40 we have:
A=3000
B=2400
A=1.25B exactly what we want.
Answer: Option B
Since we have 60 per computer for B take a multiple leading to 3000 to compare with A.
Take 50 first and check.
We find that B=3000 and A=3300.
They are pretty close together and we need to widen this gap. How?
Take the next lesser number of items = 40 so that B doesn't catch up A by as much as just 300 difference.
With 40 we have:
A=3000
B=2400
A=1.25B exactly what we want.
Answer: Option B
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