sayan640
gmatphobia , thank you for the wonderful explanation.
So the general rule of the alligation , is as follows ,
We need to keep the similar quantities in the upper side of the diagram.
Here in this case , (x+2) , 3.80 and x are the values ( of chocolates/ peanuts) or dollar amounts.
So we kept them all in the upper side of the diagram.
And then subtract from their mean i.e 3.80 to find out their corresponding weights in the mixture.
Here, (x-3.80) and (3.80 - (x-2)) are the corresponding weights in the mixture that we derive.
Correct me if I am wrong in explaining the alligation concept.
gmatphobiaI have got a question for you ,
gmatphobia /
Bunuel /
KarishmaB .
In the diagram , why is it that 3.80 is bigger than (x+2) ? ; gmatphobia wrote 3.80 - (x+2). Why ?Or for that matter , how do you know that x is bigger than 3.80 ? You wrote (x -3.80).
Please help.
gmatphobia KarishmaB Bunuelgmatphobia/
KarishmaB , Can you please help ?
There are a couple of fundamental things that are going behind the scenes (and that's why a formula-based approach is not recommended unless one knows the mechanics behind that formula)
Quote:
In the diagram , why is it that 3.80 is bigger than (x+2) ? ; gmatphobia wrote 3.80 - (x+2). Why ?Or for that matter , how do you know that x is bigger than 3.80 ? You wrote (x -3.80).
We need to realize that (x+2) > (x), and as the mixture contains more quantity of peanuts (why did I infer this ? Because the question states that "
ratio of 2 pounds of chocolate pieces to 3 pounds of peanuts"), the value of the mixture will be closer to the value x. Therefore 3.80 is not greater than (x+2), but is less.
The order of subtraction doesn't matter as long as you're keeping the ratios intact.
For example, x : y = 2:1 is the same as y : x = 1:2. So the quantity we are expressing in numerator and denominator matters.
So whether we solve ⇒
\( \frac{\text{Peanuts}}{\text{Chocolate Pieces}} = \frac{(x+2) - 3.8}{3.8-x}\)
\( \frac{3}{2} = \frac{(x+2) - 3.8}{3.8-x}\) ➾, In this case, the values of the numerator and denominator are positive
\((3 * 3.8) - 3x = 2x + 4 - (2*3.8)\)
\(x = 3.8 - 0.8 = 3\)
or we solve \( \frac{\text{Chocolate Pieces}}{\text{Peanuts}} = \frac{x - 3.8 }{3.8 - (x+2)}\)
\( \frac{2}{3} = \frac{x - 3.8 }{3.8 - (x+2)}\) ➾, In this case, the values of the numerator and denominator are negative and they cancel out.
\((2 * 3.8) - 2x - 4 = 3x - (3.8 * 3)\)
\(x = 3.8 - 0.8 = 3\)
we would get the same value.Hope this helps.