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Updated on: 21 Jul 2024, 02:50
Originally posted by Sajjad1994 on 03 May 2021, 00:52.
Last edited by Bunuel on 21 Jul 2024, 02:50, edited 3 times in total.
Last edited by Bunuel on 21 Jul 2024, 02:50, edited 3 times in total.
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Dropdown 1: R = 3
Dropdown 2: never
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
42% (02:36) correct
58%
(03:05)
wrong
based on 323
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Complete the following statements by making selections from the drop-down menus in accordance with the algorithm represented by the flowchart.
1. If 58 and 11 are entered as the values for a and b, respectively, then one of the outputs of the function will be .
2. The algorithm will get stuck in an infinite loop, .
Attachment:
1.jpg [ 32.15 KiB | Viewed 7286 times ]
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Dropdown 1: R = 3
Dropdown 2: never
11 Jun 2021, 03:11
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a equal to 58 b equal to 11
a/b is not a integer.
Therefore iteration 1:
New value of a is equal to 57 R equal to 1
Iteration 2:
a/b is not an integer 57/11
Therefore new value of a is 56 and R equal to 2
Iteration 3:
56/11 a/b not an integer
New value of a is 55
R is equal to 3
Iteration 4:
55/11 a/b equal to 5
Hence integer, Hence D equal to 5 R equal to 3
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a/b is not a integer.
Therefore iteration 1:
New value of a is equal to 57 R equal to 1
Iteration 2:
a/b is not an integer 57/11
Therefore new value of a is 56 and R equal to 2
Iteration 3:
56/11 a/b not an integer
New value of a is 55
R is equal to 3
Iteration 4:
55/11 a/b equal to 5
Hence integer, Hence D equal to 5 R equal to 3
Posted from my mobile device
14 Dec 2021, 01:28
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Initial Analysis - THe Algorithim taks in 2 numbers a, b and then divided a by b. If the result is an integer, then D ad R are output.
If D is not an integer, then R is incremented by 1, a is reduced by 1 and so on.., till a/b yields an Integer.
So, as a keeps getting reduced by 1, at one point, it will become 0. So, the algorihim can never get stuck in an infinite loop.
1)
D R a b D = a/b
0 0 58 11 Not integer
1 57 11 Not integer
2 56 11 Not integer
3 55 11 55
Exits.
So, R = 3 and D = 5. From the options, please choose D.
2) Please see the Initial Analysis. As a keeps getting reduced by 1, at one point, it will become 0.
Let us check the options.
A. if a > b - As we saw in the 1st question, a = 58, b = 11, the algorithim ended. option Rejected.
B. if a = b - if a = b, a/b = 1, option Rejected.
C. if a < b - Please see the Initial Analysis. At one point, a will become 0 Rejected.
D. never - RIGHT ANSWER.
If D is not an integer, then R is incremented by 1, a is reduced by 1 and so on.., till a/b yields an Integer.
So, as a keeps getting reduced by 1, at one point, it will become 0. So, the algorihim can never get stuck in an infinite loop.
1)
D R a b D = a/b
0 0 58 11 Not integer
1 57 11 Not integer
2 56 11 Not integer
3 55 11 55
Exits.
So, R = 3 and D = 5. From the options, please choose D.
2) Please see the Initial Analysis. As a keeps getting reduced by 1, at one point, it will become 0.
Let us check the options.
A. if a > b - As we saw in the 1st question, a = 58, b = 11, the algorithim ended. option Rejected.
B. if a = b - if a = b, a/b = 1, option Rejected.
C. if a < b - Please see the Initial Analysis. At one point, a will become 0 Rejected.
D. never - RIGHT ANSWER.
