Last visit was: 27 Apr 2024, 02:25 It is currently 27 Apr 2024, 02:25

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Tags:
Difficulty: Sub 505 Levelx   Geometryx                        
Show Tags
Hide Tags
User avatar
Manager
Manager
Joined: 02 Dec 2012
Posts: 172
Own Kudos [?]: 23867 [19]
Given Kudos: 23
Send PM
Math Expert
Joined: 02 Sep 2009
Posts: 92951
Own Kudos [?]: 619316 [3]
Given Kudos: 81611
Send PM
Director
Director
Joined: 03 Feb 2011
Status:Retaking after 7 years
Posts: 860
Own Kudos [?]: 4468 [0]
Given Kudos: 221
Location: United States (NY)
Concentration: Finance, Economics
GMAT 1: 720 Q49 V39
GPA: 3.75
Send PM
Current Student
Joined: 10 Mar 2013
Posts: 360
Own Kudos [?]: 2698 [0]
Given Kudos: 200
Location: Germany
Concentration: Finance, Entrepreneurship
GMAT 1: 580 Q46 V24
GPA: 3.7
WE:Marketing (Telecommunications)
Send PM
Re: The length of the edging that surrounds circular garden K is [#permalink]
When you can find a radius, then you can calculate both area and circumference of a circle. (D)
Intern
Intern
Joined: 10 Aug 2015
Posts: 20
Own Kudos [?]: 56 [0]
Given Kudos: 232
Location: India
GMAT 1: 700 Q48 V38
GPA: 3.5
WE:Consulting (Computer Software)
Send PM
Re: The length of the edging that surrounds circular garden K is [#permalink]
Walkabout wrote:
The length of the edging that surrounds circular garden K is 1/2 the length of the edging that surrounds circular garden G. What is the area of garden K (Assume that the edging has negligible width.)

(1) The area of G is \(25\pi\) square meters.
(2) The edging around G is \(10\pi\) meters long.


The question is very easy and above solutions are excellent. Just want to highlight one part the ratio of two circles circumference = the ratio of their radii, a fact that is very clear to see and saves us time.
Target Test Prep Representative
Joined: 04 Mar 2011
Status:Head GMAT Instructor
Affiliations: Target Test Prep
Posts: 3043
Own Kudos [?]: 6279 [0]
Given Kudos: 1646
Send PM
Re: The length of the edging that surrounds circular garden K is [#permalink]
Expert Reply
Walkabout wrote:
The length of the edging that surrounds circular garden K is 1/2 the length of the edging that surrounds circular garden G. What is the area of garden K (Assume that the edging has negligible width.)

(1) The area of G is \(25\pi\) square meters.
(2) The edging around G is \(10\pi\) meters long.


Solution:

We are given that the length of edging that surrounds circular garden K is ½ the length of the edging that surrounds circular garden G. Since the gardens are circular, we know that the circumference of garden K is ½ the circumference of circular garden G. We will use the circumference formula C = 2∏r. If we let G = the radius of garden G, and K = the radius of garden K, we can create the following equation.

2∏K = ½(2∏G)

We need to determine the area of garden K, using the area formula A = ∏r^2. Since K = the radius of garden K, we know:

Area of garden K = ∏K^2

Thus, if we can determine the value of K, we can determine the area of garden K.

Statement One Alone:

The area of G is 25∏ square meters.

We can use the information in statement one to determine the value of the radius of garden G.

25∏ = ∏G^2

25 = G^2

√25 = √G^2

5 = G

Since we have the value of G, we can determine the circumference of garden G.

circumference of garden G = 2∏G

circumference = 2∏ x 5

circumference = 10∏

From the given information we also know that:

2∏K = ½(2∏G)

Since 10∏ is the circumference of garden G, we can substitute 10∏ for 2∏G in the equation 2∏K = ½(2∏G). We can now determine a value for K.

2∏K = ½(10∏)

2∏K = 5∏

K = 2.5

Since the radius of garden K is 2.5, we have enough information to determine the area of garden K. Statement one alone is sufficient to answer the question. We can eliminate answer choices B, C, and E.

Statement Two Alone:

The edging around G is 10∏ meters long.

Using the information in statement two, we know that the circumference of garden G is 10∏.

Recall that in statement one, we already determined that the circumference of garden G is 10∏. This is enough information to determine the radius of garden K and hence the area of garden K. Statement two alone is also sufficient to answer the question.

The answer is D.
User avatar
Manager
Manager
Joined: 03 May 2015
Posts: 129
Own Kudos [?]: 232 [0]
Given Kudos: 23
Location: South Africa
Concentration: International Business, Organizational Behavior
GPA: 3.49
WE:Web Development (Insurance)
Send PM
Re: The length of the edging that surrounds circular garden K is [#permalink]
Solving DS questions is a really big waste of time

From stem : 2(pi)(rad-k) = 2(pi)(rad-g)/2 : so rad-k = rad-g/2.

radius can't be -ve. So we just have to make sure that we've one +ve rad-g

A) area given. One +ve soln. Enough
2) rad of g can be derived directly.

D
Re: The length of the edging that surrounds circular garden K is [#permalink]
Quote:
The length of the edging that surrounds circular garden K is \(\frac{1}{2}\) the length of the edging that surrounds circular garden G. What is the area of garden K (Assume that the edging has negligible width.)

(1) The area of G is \(25\pi\) square meters.
(2) The edging around G is \(10\pi\) meters long.


Here, there are 2 circles and each circle relates to each other (circumference of circle K is half of the circumference circle G).
Note:
If you're given any measure (e.g., circumference, radius, diameter, area) of G, you can calculate any measure (e.g., circumference, radius, diameter, area) of K for sure!
So, you can easily find the followings:
circumference of K=\(\frac{1}{2}\) × circumference of G
radius of K=\(\frac{1}{2}\) × radius of G
Area of K=\(\frac{1}{4}\) ×Area of G
Quote:
(1) The area of G is \(25\pi\) square meters.

You can find radius of G from here, then you can calculate radius of K, then the area of K.
-->Sufficient

Quote:
(2) The edging around G is \(10\pi\) meters long.

You can find radius of G from here, then you can calculate radius of K, then the area of K.
-->Sufficient
So the answer is D
Hope it helps...
User avatar
Non-Human User
Joined: 09 Sep 2013
Posts: 32704
Own Kudos [?]: 822 [0]
Given Kudos: 0
Send PM
Re: The length of the edging that surrounds circular garden K is [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
GMAT Club Bot
Re: The length of the edging that surrounds circular garden K is [#permalink]
Moderator:
Math Expert
92950 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne