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The line represented by the equation y = 4 – 2x is the perpendicular 18 Feb 2012, 18:55
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D
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The line represented by the equation y = 4 – 2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P?

(A) (–4, 1)
(B) (–2, 2)
(C) (0, 1)
(D) (0, –1)
(E) (2, 0)

Show Spoiler
How come the answer will be D? This is how I am trying to solve this.

First, rewrite the line y=4-2x as y = -2x+4 The equation is now in the form y = mx+b where m represents the slope and b represents the y-intercept.Thus, the slope of this line is -2. By definition, if a line is the perpendicular bisector of any line, the slope of line which is perpendicular bisector is the negative inverse of the slope of line G. Since we are told that the line y = -2x+4 is the perpendicular bisector of line segment RP, line segment RP
must have a slope of \(\frac{1}{2}\) (which is the negative inverse of slope of line y).
Now we know that the slope of the line containing segment RP is\(\frac{1}{2}\) but we do
not know its y-intercept. We can write the equation of this line as , y = 1/2x+b, where b represents the unknown y-intercept.
To solve for b, we can use the given information that the coordinates of point R
are (4, 1). Since point R is on the line y = 1/2x+b, we can plug 4 in for x and 1 in for y to get b = -1
Therefore, equation of line RP will become y = 1/2x-1
Also , y = -2x +4 (Equation of perpendicular bisector) -----------------(2)

Equating the two we will get x =2 . Putting this value of x in we get y = 0.

So the points should be (2,0) i.e. answer E.

Where I am getting this wrong guys?
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D
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priyalr
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The line represented by the equation y = 4 – 2x is the perpendicular 25 Feb 2012, 07:34
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Hello,

This is how I solved the problem. Since the Slope of line is -2, the line perpendicular to it would have SLope as 1/2. So I used R(4,1) and each options to see which one gives Slope as 1/2. Only option D gives me the co ordinates through which the SLope is 1/2. It took me around a minutes time to solve.

Please let me know if I'm correct ?
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The line represented by the equation y = 4 – 2x is the perpendicular 18 Feb 2012, 19:12
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The line represented by the equation y = 4 – 2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P?

A. (–4, 1)
B. (–2, 2)
C. (0, 1)
D. (0, –1)
E. (2, 0)

Again, there is no need of equations to solve this question. Plot the line y = 4 – 2x (just find the x and y intercepts and draw the line through them):
Attachment:
Bisector.png
Bisector.png [ 16 KiB | Viewed 65108 times ]
Now, it's easy to SEE that no blue point can be the mirror reflection of R around the line but (0, -1).

Answer: D.

P.S. Answer cannot possibly be E (2, 0) as this point lies on the line y=4-2x (substitute the values of x and y to see that it's true).
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The line represented by the equation y = 4 – 2x is the perpendicular 25 Feb 2012, 09:30
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priyalr
Hello,

This is how I solved the problem. Since the Slope of line is -2, the line perpendicular to it would have SLope as 1/2. So I used R(4,1) and each options to see which one gives Slope as 1/2. Only option D gives me the co ordinates through which the SLope is 1/2. It took me around a minutes time to solve.

Please let me know if I'm correct ?
Show more

That's perfectly valid approach.

Two lines are perpendicular if and only the product of their slopes is -1. The slope of given line is -2, hence the slope of PR must be 1/2 (negative reciprocal of -2): 1/2*(-2)=-1.

Now, the slope of a line (a line segment) passing through two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(m=\frac{y_2-y_1}{x_2-x_1}\).

So, for our case the slope of PR must be \(m=\frac{1}{2}=\frac{1-y_1}{4-x_1}\) and you can substitute x and y coordinates of each point from answer choices to see for which one this equation will hold true. Only coordinates of a point from option D fits.
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The line represented by the equation y = 4 – 2x is the perpendicular 01 Jul 2012, 03:10
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Bunuel
priyalr
Hello,

This is how I solved the problem. Since the Slope of line is -2, the line perpendicular to it would have SLope as 1/2. So I used R(4,1) and each options to see which one gives Slope as 1/2. Only option D gives me the co ordinates through which the SLope is 1/2. It took me around a minutes time to solve.

Please let me know if I'm correct ?

That's perfectly valid approach.

Two lines are perpendicular if and only the product of their slopes is -1. The slope of given line is -2, hence the slope of PR must be 1/2 (negative reciprocal of -2): 1/2*(-2)=-1.

Now, the slope of a line (a line segment) passing through two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(m=\frac{y_2-y_1}{x_2-x_1}\).


So, for our case the slope of PR must be \(m=\frac{1}{2}=\frac{1-y_1}{4-x_1}\) and you can substitute x and y coordinates of each point from answer choices to see for which one this equation will hold true. Only coordinates of a point from option D fits.
Show more

let's have a look
Required slope for line PR = m= 1/2 ( using if two lines are perpendicular then their slopes m1 * m2 = -1 )
option D= ( 0,-1)
Option E = ( 2, 0)

so taking (4,1) and ( 0,-1) and finding slope
= -2/-4 = 1/2 which is of course what we are expecting ,

now taking (4,1) and (2,0) and finding slope

= -1/-2 = 1/2

So also E, satisfies the slope method
So what am I missing , it is said that only one option satisfies the equation 1/2 = (1-y1)/( 4-x1)
Taking E( 2,0)
(1-0)/(4-2) = 1/2

and taking D(0,-1)
(1+1)/(4-0)= 2/4= 1/2

so both D and E satisfy the slope condition , am I missing anything ?
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The line represented by the equation y = 4 – 2x is the perpendicular 01 Jul 2012, 03:37
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Bunuel
priyalr
Hello,

This is how I solved the problem. Since the Slope of line is -2, the line perpendicular to it would have SLope as 1/2. So I used R(4,1) and each options to see which one gives Slope as 1/2. Only option D gives me the co ordinates through which the SLope is 1/2. It took me around a minutes time to solve.

Please let me know if I'm correct ?

That's perfectly valid approach.

Two lines are perpendicular if and only the product of their slopes is -1. The slope of given line is -2, hence the slope of PR must be 1/2 (negative reciprocal of -2): 1/2*(-2)=-1.

Now, the slope of a line (a line segment) passing through two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(m=\frac{y_2-y_1}{x_2-x_1}\).


So, for our case the slope of PR must be \(m=\frac{1}{2}=\frac{1-y_1}{4-x_1}\) and you can substitute x and y coordinates of each point from answer choices to see for which one this equation will hold true. Only coordinates of a point from option D fits.

let's have a look
Required slope for line PR = m= 1/2 ( using if two lines are perpendicular then their slopes m1 * m2 = -1 )
option D= ( 0,-1)
Option E = ( 2, 0)

so taking (4,1) and ( 0,-1) and finding slope
= -2/-4 = 1/2 which is of course what we are expecting ,

now taking (4,1) and (2,0) and finding slope

= -1/-2 = 1/2

So also E, satisfies the slope method
So what am I missing , it is said that only one option satisfies the equation 1/2 = (1-y1)/( 4-x1)
Taking E( 2,0)
(1-0)/(4-2) = 1/2

and taking D(0,-1)
(1+1)/(4-0)= 2/4= 1/2

so both D and E satisfy the slope condition , am I missing anything ?
Show more

You can rule out (2,0) (option E), since this point is on the line y=4-2x.
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The line represented by the equation y = 4 – 2x is the perpendicular 26 Oct 2012, 06:29
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Bunuel Bro, my question still remains : I understand E is on the line but why does E also result in slope of 1/2 . . E should cause the slope to be -2 since it is on the line. . why does it then cause the slope to be 1/2?

just trying to understand the math of slope here.
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The line represented by the equation y = 4 – 2x is the perpendicular 26 Oct 2012, 06:41
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sachindia
Bunuel Bro, my question still remains : I understand E is on the line but why does E also result in slope of 1/2 . . E should cause the slope to be -2 since it is on the line. . why does it then cause the slope to be 1/2?

just trying to understand the math of slope here.
Show more

Point (2, 0) is on line segment PR (see diagram in my post above). PR is perpendicular to line y = 4 – 2x, thus ANY two point from line segment PR will give you the slope which is negative reciprocal of the slope of line y = 4 – 2x, i.e. 1/2.
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The line represented by the equation y = 4 – 2x is the perpendicular 26 Oct 2012, 09:52
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Concrete way is to find the actual co-ordinates.

Slope of RP = 1/2 and by using 4,1 and slope the equation is y=x/2 -1

solve for point of intersection - x,y = 2,0.

now let P has co-ordinates (x,y)

since intersection is mid point.

(x+4)/2 = 2 and (y+1)/2 = 0 thus D
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The line represented by the equation y = 4 – 2x is the perpendicular 02 Nov 2012, 00:45
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Quote:
solve for point of intersection - x,y = 2,0.
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How do you get to know the point of intersection is 2,0?

I understood your solution till the previous step in which you found the equation of the line.
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The line represented by the equation y = 4 – 2x is the perpendicular 02 Nov 2012, 02:07
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Quote:
solve for point of intersection - x,y = 2,0.

How do you get to know the point of intersection is 2,0?

I understood your solution till the previous step in which you found the equation of the line.
Show more

x-intercept is a value of x for y=0 and similarly y-intercept is a value of y for x=0.

To find x-intercept substitute y=0 and find x.
To find y-intercept substitute x=0 and find y.

For more check Coordinate Geometry chapter of Math Book: math-coordinate-geometry-87652.html

Hope it helps.
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The line represented by the equation y = 4 – 2x is the perpendicular 11 Nov 2012, 08:08
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Bunuel, do you think these coordinates are not unique.
Any combination (x,y) for point P that satisfies the equation 2-2*y = 4-x will make RP perpendicular to the line y = 4-2x.
Am I correct to assert that?
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The line represented by the equation y = 4 – 2x is the perpendicular 12 Nov 2012, 10:02
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Ousmane
Bunuel, do you think these coordinates are not unique.
Any combination (x,y) for point P that satisfies the equation 2-2*y = 4-x will make RP perpendicular to the line y = 4-2x.
Am I correct to assert that?
Brother Karamazov
Show more

No, that's not correct. Line y = 4 – 2x not only has to be perpendicular of PR but also has to be bisector of PR (line y = 4 -2x cuts PR into two equal parts at 90°). Therefore the coordinates of P are unique.

Hope it's clear.
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The line represented by the equation y = 4 – 2x is the perpendicular 01 Sep 2017, 11:59
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enigma123
The line represented by the equation y = 4 – 2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P?

(A) (–4, 1)
(B) (–2, 2)
(C) (0, 1)
(D) (0, –1)
(E) (2, 0)

Show more

If the line y = 4 - 2x is the perpendicular bisector of line segment RP, then it’s perpendicular to RP at the midpoint of RP. Recall that two lines are perpendicular if their slopes are negative reciprocals of each other. Since the line has a slope of -2, the line segment should have a slope of ½. Thus, let’s first determine which answer choice can be point P so that the slope of RP is ½. We’ll use the slope formula: m = (y2 - y1)/(x2 - x1):

A) (-4, 1)

m = (1 - 1)/(4 - (-4)) = 0

Point P can’t be (-4, 1).

B) (-2, 2)

m = (1 - 2)/(4 - (-2)) = -1/6

Point P can’t be (-2, 2).

C) (0, 1)

m = (1 - 1)/(4 - 0) = 0

Point P can’t be (0, 1).

D) (0, -1)

m = (1 - (-1))/(4 - 0) = 2/4 = 1/2

Point P could be (0, -1).

E) (2, 0)

m = (1 - 0)/(4 - 2) = 1/2

Point P could be (2, 0).

We see that point P could be either (0, -1) or (2, 0), since either one will make RP’s slope ½. Next let’s determine the midpoint of RP if P is either (0, -1) or (2, 0). We use the midpoint formula: ((x1 + x2)/2 , (y1 + y2)/2)). Recall that R = (4,1).

If P = (0, -1), then the midpoint of RP = ((4 + 0)/2, (1 + (-1))/2) = (2, 0).

If P = (2, 0), then the midpoint of RP = ((4 + 2)/2, (1 + 0)/2) = (3, 1/2).

Recall that the line y = 4 - 2x has to include the midpoint of RP. In other words, the midpoint of RP is a point on the line, and hence its coordinates will satisfy the equation of the line.

If P = (0, -1) and the midpoint of RP is (2, 0), is 0 = 4 - 2(2)? The answer is yes, since 0 = 0. We can see that choice D is the correct choice. However, let’s also show that choice E is not the correct choice:

If P = (2, 0) and the midpoint of RP is (3, 1/2), is 1/2 = 4 - 2(3)? The answer is no, since 1/2 ≠ -2.

Alternate Solution:

Since the line segment RP is perpendicular to y = 4 - 2x, the line containing RP must have a slope of 1/2, since the slopes of perpendicular lines are negative reciprocals of each other. Then, the line containing the line segment RP must be of the form y = (1/2)x + b, for some real number b. Since this line contains the point R, its equation must be satisfied when we substitute x = 4 and y = 1; therefore 1 = (1/2)(4) + b. Then, 1 = 2 + b, and thus b = -1.

We know the line that contains the line segment RP has an equation y = (1/2)x - 1. Let’s find the common point of this line with y = 4 - 2x. We set (1/2)x - 1 = 4 - 2x and solve for x:

(1/2)x -1 = 4 - 2x

(5/2)x = 5

x = 2

So, the x-coordinate of the common point is 2. We can substitute x = 2 in either equation to find the y-coordinate: y = 4 - 2(2) = 0. So, the common point is (2, 0).

Note that this common point is the midpoint of R and P. Therefore, if we let P = (a, b), we must have:

(a + 4)/2 = 2 and (b + 1)/2 = 0. We find that a = 0 and b = -1. Thus, P = (0, -1).

Answer: D
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The line represented by the equation y = 4 – 2x is the perpendicular 06 Oct 2019, 10:08
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enigma123
The line represented by the equation y = 4 – 2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P?

(A) (–4, 1)
(B) (–2, 2)
(C) (0, 1)
(D) (0, –1)
(E) (2, 0)

Show Spoiler
How come the answer will be D? This is how I am trying to solve this.

First, rewrite the line y=4-2x as y = -2x+4 The equation is now in the form y = mx+b where m represents the slope and b represents the y-intercept.Thus, the slope of this line is -2. By definition, if a line is the perpendicular bisector of any line, the slope of line which is perpendicular bisector is the negative inverse of the slope of line G. Since we are told that the line y = -2x+4 is the perpendicular bisector of line segment RP, line segment RP
must have a slope of \(\frac{1}{2}\) (which is the negative inverse of slope of line y).
Now we know that the slope of the line containing segment RP is\(\frac{1}{2}\) but we do
not know its y-intercept. We can write the equation of this line as , y = 1/2x+b, where b represents the unknown y-intercept.
To solve for b, we can use the given information that the coordinates of point R
are (4, 1). Since point R is on the line y = 1/2x+b, we can plug 4 in for x and 1 in for y to get b = -1
Therefore, equation of line RP will become y = 1/2x-1
Also , y = -2x +4 (Equation of perpendicular bisector) -----------------(2)

Equating the two we will get x =2 . Putting this value of x in we get y = 0.

So the points should be (2,0) i.e. answer E.

Where I am getting this wrong guys?
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The line represented by the equation y = 4 – 2x is the perpendicular 06 Oct 2019, 11:15
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enigma123
The line represented by the equation y = 4 – 2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P?

(A) (–4, 1)
(B) (–2, 2)
(C) (0, 1)
(D) (0, –1)
(E) (2, 0)

Show Spoiler
How come the answer will be D? This is how I am trying to solve this.

First, rewrite the line y=4-2x as y = -2x+4 The equation is now in the form y = mx+b where m represents the slope and b represents the y-intercept.Thus, the slope of this line is -2. By definition, if a line is the perpendicular bisector of any line, the slope of line which is perpendicular bisector is the negative inverse of the slope of line G. Since we are told that the line y = -2x+4 is the perpendicular bisector of line segment RP, line segment RP
must have a slope of \(\frac{1}{2}\) (which is the negative inverse of slope of line y).
Now we know that the slope of the line containing segment RP is\(\frac{1}{2}\) but we do
not know its y-intercept. We can write the equation of this line as , y = 1/2x+b, where b represents the unknown y-intercept.
To solve for b, we can use the given information that the coordinates of point R
are (4, 1). Since point R is on the line y = 1/2x+b, we can plug 4 in for x and 1 in for y to get b = -1
Therefore, equation of line RP will become y = 1/2x-1
Also , y = -2x +4 (Equation of perpendicular bisector) -----------------(2)

Equating the two we will get x =2 . Putting this value of x in we get y = 0.

So the points should be (2,0) i.e. answer E.

Where I am getting this wrong guys?
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Equation of Perpendicular Bisector is
Y=4-2X
Equation of a line perpendicular to this line
Y=1/2X+C
This line passes through (4,1)
1=1/2 *4 +C
C=-1
Equation of line through which perpendicular bisector passes or equation of line RP is
Y=1/2 X-1
Coordinates of point P must pass through this Equation
At X=0, Y=-1
So (0,-1) But (2,0) also satisfies this condition.
If (2,0) is the coordinates of point P
Then Mid point of RP(3,1/2), and this must be pass through the line of perpendicular bisector
i.e
Y=4-2X
at X =3, Y=-2( Not 1/2)
So (2,0) is not the coordinates of point P
D:)
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The line represented by the equation y = 4 – 2x is the perpendicular 09 Oct 2019, 03:18
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for eqn y = 4 – 2x
slope= -2
so for line with coordiante (4,1) the slope should be 1/2
since both are perpendicular so m1*m2=-1
we get 1/2 for (4,1) & ( 0,-1) only
IMO D



enigma123
The line represented by the equation y = 4 – 2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P?

(A) (–4, 1)
(B) (–2, 2)
(C) (0, 1)
(D) (0, –1)
(E) (2, 0)

Show Spoiler
How come the answer will be D? This is how I am trying to solve this.

First, rewrite the line y=4-2x as y = -2x+4 The equation is now in the form y = mx+b where m represents the slope and b represents the y-intercept.Thus, the slope of this line is -2. By definition, if a line is the perpendicular bisector of any line, the slope of line which is perpendicular bisector is the negative inverse of the slope of line G. Since we are told that the line y = -2x+4 is the perpendicular bisector of line segment RP, line segment RP
must have a slope of \(\frac{1}{2}\) (which is the negative inverse of slope of line y).
Now we know that the slope of the line containing segment RP is\(\frac{1}{2}\) but we do
not know its y-intercept. We can write the equation of this line as , y = 1/2x+b, where b represents the unknown y-intercept.
To solve for b, we can use the given information that the coordinates of point R
are (4, 1). Since point R is on the line y = 1/2x+b, we can plug 4 in for x and 1 in for y to get b = -1
Therefore, equation of line RP will become y = 1/2x-1
Also , y = -2x +4 (Equation of perpendicular bisector) -----------------(2)

Equating the two we will get x =2 . Putting this value of x in we get y = 0.

So the points should be (2,0) i.e. answer E.

Where I am getting this wrong guys?
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The line represented by the equation y = 4 – 2x is the perpendicular 01 Jun 2020, 00:23
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slope of line y=4-2x is -2
slope of RP = 1/2 (perpendicular bisector)
To find equation of line RP y = mx+c
put m = 1/2 y=1 and x=4 to find C (Rs coordinates given 4,1)
upon solving, c=-1

equation of line RP is y=1/2x- 1
Point P lies on this line and hence will have to satisfy the equation
ONLY points (0,-1) satisfies this equation
-1=-1 hence D
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The line represented by the equation y = 4 – 2x is the perpendicular 13 Aug 2021, 06:18
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Bunuel
The line represented by the equation y = 4 – 2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P?

A. (–4, 1)
B. (–2, 2)
C. (0, 1)
D. (0, –1)
E. (2, 0)

Again, there is no need of equations to solve this question. Plot the line y = 4 – 2x (just find the x and y intercepts and draw the line through them):
Attachment:
Bisector.png
Now, it's easy to SEE that no blue point can be the mirror reflection of R around the line but (0, -1).

Answer: D.

P.S. Answer cannot possibly be E (2, 0) as this point lies on the line y=4-2x (substitute the values of x and y to see that it's true).
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Hi Bunuel, I followed a similar approach but did not solve by plotting the points to scale for calculating R. Instead i figured that the R must be 180 degree opposite to point P and should also be 90 degree opposite the line (meaning the simplified line equation y = -x acts as a mirror ). Therefore, the point R should lie in 3rd or 4th quadrant. Only 1 option had negative sign for y coordinate and i picked that as my answer.

I want to know if this reasoning is correct? (i know if there are multiple options with negative y coordinates, this approach will not work)
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The line represented by the equation y = 4 – 2x is the perpendicular 30 Aug 2021, 06:56
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enigma123
The line represented by the equation y = 4 – 2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P?

(A) (–4, 1)
(B) (–2, 2)
(C) (0, 1)
(D) (0, –1)
(E) (2, 0)

[/spoiler]
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IMO D

Given:
y = 4 - 2x
can be written as
y = -2x + 4
so slope = -2 ---> slope of perpendicular line RP = 1/2

Slope point form: m = 1/2 ; Point (4,1)
Substitute choices in m = (y2-y1) / (x2-x1) to get 1/2

So, answer is D
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