Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

The organizers of a fair projected a 25 percent increase in attendance this year over that of last year, but attendance this year actually decreased by 20 percent. What percent of the projected attendance was the actual attendance?

(A) 45% (B) 56% (C) 64% (D) 75% (E) 80%

Problem Solving Question: 38 Category:Arithmetic Percents Page: 66 Difficulty: 600

Each week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

The organizers of a fair projected a 25 percent increase in attendance this year over that of last year, but attendance this year actually decreased by 20 percent. What percent of the projected attendance was the actual attendance?

(A) 45% (B) 56% (C) 64% (D) 75% (E) 80%

Last year attendance = 100 (assume); Projected Attendance = 125; Actual Attendance = 80.

The actual attendance therefore was (Actual)/(Project) = 80/125 *100 = 64$ of the projected attendance.

The organizers of a fair projected a 25 percent increase in attendance this year over that of last year, but attendance this year actually decreased by 20 percent. What percent of the projected attendance was the actual attendance?

(A) 45% (B) 56% (C) 64% (D) 75% (E) 80%

Let "X" be the last year attendance . Projected attendance = 1.25X Actual attendance = 0.8X So .8/1.25 = (4/5)/(5/4) = 16/25 hence 64% - Option C) [% can be calculated faster if we notice 25*4 = 100 so 16/25 = 16*4/25*4 = 64/100 = 64%]
_________________

Re: The organizers of a fair projected a 25 percent increase in [#permalink]

Show Tags

14 Jan 2014, 22:22

1

This post received KUDOS

Let us assume the last year attendance as 100(easiest number to pick, since all are in percent). Projected attendance = 25% increase(of 100) = 125 Actual attendance = 20% decrease(of 100) = 80

I took \(\frac{80}{125}\) and reduced it to \(\frac{16}{25}\) and couldn't figure it out past that

sooooo

I made it \(\frac{15}{25}\) and reduced it into \(\frac{3}{5}\) and then multiplied it by two to get \(\frac{6}{10}=60%\) and since \(16>15\) \(\frac{16}{25}\)>\(60%\)

Re: The organizers of a fair projected a 25 percent increase in [#permalink]

Show Tags

18 Jan 2014, 23:46

2

This post received KUDOS

The organizers of a fair projected a 25 percent increase in attendance this year over that of last year, but attendance this year actually decreased by 20 percent. What percent of the projected attendance was the actual attendance?

Re: The organizers of a fair projected a 25 percent increase in [#permalink]

Show Tags

19 Jan 2014, 00:28

1

This post received KUDOS

arunspanda wrote:

The organizers of a fair projected a 25 percent increase in attendance this year over that of last year, but attendance this year actually decreased by 20 percent. What percent of the projected attendance was the actual attendance?

Re: The organizers of a fair projected a 25 percent increase in [#permalink]

Show Tags

23 Apr 2014, 03:58

1

This post received KUDOS

Let Last year attendance be X; Then Projected Attendance will be 1.25x ; Actual attendance will be 0.8x; Question is asking us 0.8x is what percent of 1.25x ?

Questions with "What is X percent of Y" translates to

"What" translates to " Unknown " "is" translates to " = " "X" translates to " X " "percent" translates to " /100 " "of" translates to multiplication sign " * " "Y" translates to "Y"

Hence Unknown = (X/100) * Y

Use the same logic and Smart Numbers in order to decode the question and generate the formula. You should end up with

Actual = X/100 Projected ... Plug the numbers and solve with respect to X. The answer should be C

The organizers of a fair projected a 25 percent increase in attendance this year over that of last year, but attendance this year actually decreased by 20 percent. What percent of the projected attendance was the actual attendance?

(A) 45% (B) 56% (C) 64% (D) 75% (E) 80%

Say '\(x\)' is your total attendance last year. Projected attendance: \(\cfrac { 5 }{ 4 } x\) Actual attendance: \(\cfrac { 4 }{ 5 } x\) '\(z\)' is the 'What percent of the projected attendance the actual attendance was'