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Let p = price per kilogram of the premium fertilizer and r = the price per kilogram of the regular fertilizer
We know then that 5p=6r and we also know that p=y+r, both from the premise given.
From this we know that p=y+r=6/5r by combining the two expressions.
From this simply solve for r in terms of y to get y = 1/5 r, and 5y = r.
Now, back solve from out expression that p=6/5r=6/5*5y=6y.
Choice E
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Answer = E) 6y

Let price of 5kg premium = price of 6kg regular = a

Price of 1 Kg premium\(= \frac{a}{5}\)

Price of 1 Kg regular \(=\frac{a}{6}\)

Given that \(\frac{a}{6} + y = \frac{a}{5}\)

\(\frac{a}{30} = y\)

\(\frac{a}{5} = 6y\)
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I'm mostly posting the same solution that everyone else is, but typing the solution out as if you are teaching someone helps solidify the information in your memory.

Using "p" for premium and "r" for regular, I got two equations from the question stem:

5p = 6r and p = r+y

Substitute for p: 5(r+y) = 6r
Distribute: 5r + 5y = 6r
Subtract 5r from both sides: 5y = r
Plug back into the first equation: 5p = 6(5y)
Distribute: 5p = 30y
Divide both sides by 5: p = 6y

The answer is E.
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Bunuel

Tough and Tricky questions: Word Problems.



The price of 5 kilograms of premium fertilizer is the same as the price of 6 kilograms of regular fertilizer. If the price of premium fertilizer is y cents per kilogram more than the price of regular fertilizer, what is the price, in cents, per kilogram of premium fertilizer?

A) y/30
B) 5/6*y
C) 6/5*y
D) 5y
E) 6y

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Source: Chili Hot GMAT

The correct answer is E.
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