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Re: The product of the five distinct integers a, b, c, d and e is 2310. If [#permalink]
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Antonio.Salazar2887 wrote:
The product of the five distinct integers a, b, c, d and e is 2310. If a > b > c > 3 and d > 1 and e > 1, what is the value of bc - 3a?

A. -24
B. -6
C. 2
D. 6
E. 24


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Re: The product of the five distinct integers a, b, c, d and e is 2310. If [#permalink]
Antonio.Salazar2887 wrote:
The product of the five distinct integers a, b, c, d and e is 2310. If a > b > c > 3 and d > 1 and e > 1, what is the value of bc - 3a?

A. -24
B. -6
C. 2
D. 6
E. 24


a x b x c x d x e = 2310.
Prime factorization of 2310 = 2 x 3 x 5 x 7 x 11
Given; a > b > c > 3
Therefore a = 11, b = 7, c = 5
Value of bc - 3a = (7 x 5) - (3 x 11) = 35 - 33 = 2.
Answer C...
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Re: The product of the five distinct integers a, b, c, d and e is 2310. If [#permalink]
a * b * c * d * e = 2310 = 2*3*5*7*11
a > b > c > 3 and d > 1 and e > 1
Comparing, we get
a=11, b=7, c=5
bc - 3a = 35 - 33 = 2
Hence, OA is (C).
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Re: The product of the five distinct integers a, b, c, d and e is 2310. If [#permalink]
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