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The "Racing magic" takes 120 seconds to circle the racing track once. [#permalink]
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13 Jun 2016, 00:48
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47% (01:11) correct 53% (01:41) wrong based on 132 sessions
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Re: The "Racing magic" takes 120 seconds to circle the racing track once. [#permalink]
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13 Jun 2016, 01:07
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Time taken by Racing magic to make one circle = 120 seconds = 2 mins Time taken by "Charging bull" to make one circle = 60 mins / 40 = 1.5 mins = 90 seconds LCM of 90 and 120 seconds = 360 seconds = 6 mins Time taken for them to meet at the starting point for the second time = 6 mins *2 = 12 mins Answer D
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Re: The "Racing magic" takes 120 seconds to circle the racing track once. [#permalink]
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13 Jun 2016, 01:10
The "Racing magic" takes 120 seconds to circle the racing track once. The "Charging bull" makes 40 rounds of the track in an hour. If they left the starting point together, how many minutes will it take for them to meet at the starting point for the second time? A. 3 B. 6 C. 9 D. 12 E. 15 Racing magic = 120 sec Charging bull for 1 round = 60*60/40 = 90 sec LCM of 90,120 = 360 sec = 6 mins. Met for the second time after 6 mins as they met first time as they left together. B
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The "Racing magic" takes 120 seconds to circle the racing track once. [#permalink]
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13 Jun 2016, 01:49
FightToSurvive wrote: The "Racing magic" takes 120 seconds to circle the racing track once. The "Charging bull" makes 40 rounds of the track in an hour. If they left the starting point together, how many minutes will it take for them to meet at the starting point for the second time?
A. 3 B. 6 C. 9 D. 12 E. 15
Racing magic = 120 sec Charging bull for 1 round = 60*60/40 = 90 sec LCM of 90,120 = 360 sec = 6 mins. Met for the second time after 6 mins as they met first time as they left together. B i concur to same xplanation but, the question asks when will they meet of 2nd time 1st time would indeed be answer choice B but for 2nd time it will be 12 min. Correct Answer D



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Re: The "Racing magic" takes 120 seconds to circle the racing track once. [#permalink]
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13 Jun 2016, 03:03
hsbinfy wrote: FightToSurvive wrote: The "Racing magic" takes 120 seconds to circle the racing track once. The "Charging bull" makes 40 rounds of the track in an hour. If they left the starting point together, how many minutes will it take for them to meet at the starting point for the second time?
A. 3 B. 6 C. 9 D. 12 E. 15
Racing magic = 120 sec Charging bull for 1 round = 60*60/40 = 90 sec LCM of 90,120 = 360 sec = 6 mins. Met for the second time after 6 mins as they met first time as they left together. B i concur to same xplanation but, the question asks when will they meet of 2nd time 1st time would indeed be answer choice B but for 2nd time it will be 12 min. Correct Answer D confused between B and D, anybody please provide explanation



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Re: The "Racing magic" takes 120 seconds to circle the racing track once. [#permalink]
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13 Jun 2016, 05:44
RM takes 120 seconds = 2 minutes to circle once Cb takes 60/40 = 1.5 minutes to circle once They will meet after the intervals of LCM (1.5 , 2.0) = 6,12,18.. thus they will meet for the second time at 12 minutes



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Re: The "Racing magic" takes 120 seconds to circle the racing track once. [#permalink]
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13 Jun 2016, 18:12
hsbinfy wrote: FightToSurvive wrote: The "Racing magic" takes 120 seconds to circle the racing track once. The "Charging bull" makes 40 rounds of the track in an hour. If they left the starting point together, how many minutes will it take for them to meet at the starting point for the second time?
A. 3 B. 6 C. 9 D. 12 E. 15
Racing magic = 120 sec Charging bull for 1 round = 60*60/40 = 90 sec LCM of 90,120 = 360 sec = 6 mins. Met for the second time after 6 mins as they met first time as they left together. B i concur to same xplanation but, the question asks when will they meet of 2nd time 1st time would indeed be answer choice B but for 2nd time it will be 12 min. Correct Answer D the question says that they have started at the same time. which means that they have already met the first time. So, second time would be the next time they meet. i.e after 6 mins.



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Re: The "Racing magic" takes 120 seconds to circle the racing track once. [#permalink]
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05 Jul 2016, 02:09
Confused as well. Would the fact that they started from the same point be considered as their first meeting or not? Anybody...?



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The "Racing magic" takes 120 seconds to circle the racing track once. [#permalink]
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05 Jul 2016, 02:22
120 sec= 2 min =0.5 rev/min 40 rounds per hour = 40/60 = 2/3 rounds per min substitue the option The minimum value at which both the above speeds give a whole number will be the second meeting as they have met first time at the starting point... A. 0.5*3=1.5 reject B. 6*.5 =3 6*2/3= 4 B is the correct answer So after 6,12,18,24 the horses will meet Sent from my iPhone using GMAT Club Forum mobile app



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Re: The "Racing magic" takes 120 seconds to circle the racing track once. [#permalink]
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17 Nov 2017, 12:54
Bunuel wrote: The "Racing magic" takes 120 seconds to circle the racing track once. The "Charging bull" makes 40 rounds of the track in an hour. If they left the starting point together, how many minutes will it take for them to meet at the starting point for the second time?
A. 3 B. 6 C. 9 D. 12 E. 15 It is not concised question. Why the first time they have met is not 0 sec > the second time 6 mins?



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Re: The "Racing magic" takes 120 seconds to circle the racing track once. [#permalink]
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18 Nov 2017, 18:43
Yep, the question is not clear, doubt you gonna have smth confusing like that on real gmat or at least the question will be formulated differently First time they meet when they start second time in 6 mins third time in 12 mins



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Re: The "Racing magic" takes 120 seconds to circle the racing track once. [#permalink]
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19 Nov 2017, 21:26
"Racing magic" = 120 seconds or say 2 minutes The "Charging bull" makes 40 rounds of the track in an hour or say 3/2 minutes (60/40) to cover the track once. so first time they will meet at starting point LCM (2,3/2) = 6 minutes So second time they will meet at 12 minutes. NOTE : how to calculate LCM between 2 and 3/2 formula to find LCM between fractions : LCM( (a/b) , (c/d) ) = LCM(a,c)/HCF(b,d) here LCM b/w 2 & 3 is 6 HCF b/w 1 and 2 is 1 therefore LCM = 6




Re: The "Racing magic" takes 120 seconds to circle the racing track once.
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