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The ratio, by volume, of baking soda to peroxide to water in
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Updated on: 29 Oct 2012, 14:25
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The ratio, by volume, of baking soda to peroxide to water in a certain solution is 2:50:100. The solution will be altered so that the ratio of baking soda to water is halved while the ratio of baking soda to peroxide is doubled. How many cubic centimeters of water will this solution contain if the altered solution will contain 100 cubic centimeters of peroxide? A. 50 B. 200 C. 400 D. 625 E. 800 The Book does not show any answers. Hence I need to figure out if I have done them correctly or not. Please help me if you can. Would greatly appropriate it. Thanks.
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Originally posted by phoenix9801 on 01 Jun 2012, 11:19.
Last edited by Bunuel on 29 Oct 2012, 14:25, edited 2 times in total.
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Re: The ratio, by volume, of baking soda to peroxide to water in
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02 Jun 2012, 08:00
phoenix9801 wrote: The Book does not show any answers. Hence I need to figure out if I have done them correctly or not. Please help me if you can. Would greatly appropriate it. Thanks.
The ratio, by volume, of baking soda to peroxide to water in a certain solution is 2:50:100. The solution will be altered so that the ratio of baking soda to water is halved while the ratio of baking soda to peroxide is doubled. How many cubic centimeters of water will this solution contain if the altered solution will contain 100 cubic centimeters of peroxide?
A. 50 B. 200 C. 400 D. 625 E. 800 Given: \(\frac{B}{{\frac{P}{W}}}=\frac{2}{{\frac{50}{100}}}\); The ratio of baking soda to water is halved > \(\frac{B}{W}=\frac{1}{2}*\frac{2}{100}=\frac{1}{100}=\frac{4}{400}\); The ratio of baking soda to peroxide is doubled > \(\frac{B}{P}=2*\frac{2}{50}=\frac{4}{50}\); New ratio: \(\frac{B}{{\frac{P}{W}}}=\frac{4}{{\frac{50}{400}}}\) > \(\frac{P}{W}=\frac{50}{400}\) > if \(P=2*50=100\) then \(W=2*400=800\). Answer: E.
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Re: Ratio Problem 5
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02 Jun 2012, 02:19
souvik101990 wrote: Initially B:P:W=2:50:100 That is B:P=2:50 and B:W=2:100 After altering the solution B:P is halved i.e B:P now is 1:50 B:W is doubled i.e B:W now is 4:100 So in the new solution B:P:W=4:200:100 That makes P:W=2:1 So water = 50 cc A is my choice My working is similar, only thing is probably the ratios are different B:P:W=2:50:100 That is B:P=2:50 and B:W=2:100 After altering the solution B:W is halved New B:w now is 1:100 (or 4:400) B:P is doubled New B:P now is 4:50 In new solution B:P:W = 4:50:400 or 8:100:800 When P is 100cc, Water is 800cc E, it is.




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Re: Ratio Problem 5
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Re: The ratio, by volume, of baking soda to peroxide to water in
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04 Jun 2012, 12:44
Bunuel wrote: phoenix9801 wrote: The Book does not show any answers. Hence I need to figure out if I have done them correctly or not. Please help me if you can. Would greatly appropriate it. Thanks.
The ratio, by volume, of baking soda to peroxide to water in a certain solution is 2:50:100. The solution will be altered so that the ratio of baking soda to water is halved while the ratio of baking soda to peroxide is doubled. How many cubic centimeters of water will this solution contain if the altered solution will contain 100 cubic centimeters of peroxide?
A. 50 B. 200 C. 400 D. 625 E. 800 Given: \(\frac{B}{{\frac{P}{W}}}=\frac{2}{{\frac{50}{100}}}\); The ratio of baking soda to water is halved > \(\frac{B}{W}=\frac{1}{2}*\frac{2}{100}=\frac{1}{100}=\frac{4}{400}\); The ratio of baking soda to peroxide is doubled > \(\frac{B}{P}=2*\frac{2}{50}=\frac{4}{50}\); New ratio: \(\frac{B}{{\frac{P}{W}}}=\frac{4}{{\frac{50}{400}}}\) > \(\frac{P}{W}=\frac{50}{400}\) > if \(P=2*50=100\) then \(W=2*400=800\). Answer: E. Dear Bunuel, could u pls explain why this "2*50" to P and "2*400" is taken?



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Re: The ratio, by volume, of baking soda to peroxide to water in
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04 Jun 2012, 12:52
kashishh wrote: Bunuel wrote: phoenix9801 wrote: The Book does not show any answers. Hence I need to figure out if I have done them correctly or not. Please help me if you can. Would greatly appropriate it. Thanks.
The ratio, by volume, of baking soda to peroxide to water in a certain solution is 2:50:100. The solution will be altered so that the ratio of baking soda to water is halved while the ratio of baking soda to peroxide is doubled. How many cubic centimeters of water will this solution contain if the altered solution will contain 100 cubic centimeters of peroxide?
A. 50 B. 200 C. 400 D. 625 E. 800 Given: \(\frac{B}{{\frac{P}{W}}}=\frac{2}{{\frac{50}{100}}}\); The ratio of baking soda to water is halved > \(\frac{B}{W}=\frac{1}{2}*\frac{2}{100}=\frac{1}{100}=\frac{4}{400}\); The ratio of baking soda to peroxide is doubled > \(\frac{B}{P}=2*\frac{2}{50}=\frac{4}{50}\); New ratio: \(\frac{B}{{\frac{P}{W}}}=\frac{4}{{\frac{50}{400}}}\) > \(\frac{P}{W}=\frac{50}{400}\) > if \(P=2*50=100\) then \(W=2*400=800\). Answer: E. Dear Bunuel, could u pls explain why this "2*50" to P and "2*400" is taken? We have that \(\frac{P}{W}=\frac{50}{400}\) and \(P=100=2*50\). Now, if \(P=100\) then in order \(\frac{P}{W}=\frac{50}{400}\) to hold true W must be 800=2*400. Or simply: \(\frac{P}{W}=\frac{50}{400}=\frac{100}{800}\).
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Re: The ratio, by volume, of baking soda to peroxide to water in
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24 Jun 2013, 04:04



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Re: The ratio, by volume, of baking soda to peroxide to water in
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24 Jun 2013, 05:48
1. Let the volume of the original solution be v. The ratio of baking soda to peroxide to water is 2:50:100 2. v= 2x+50x+100x 3. The ratio of baking soda to peroxide is doubled and the ratio of baking soda to water is halved. 4 The volume is the same. v= 2y+25y+200y 5. We see if the peroxide is 25 cu.cm, water is 200 cu.cm. If peroxide is 100 cu.cm , water contained is 800 cu.cm
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Re: The ratio, by volume, of baking soda to peroxide to water in
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04 Jan 2014, 20:58
Ratio to BS/Perox/water = 2/50/100 ; If you halved the ratio of Perox / water =(50/100) *(1/2)= 25/100 At the same time the ratio of BS / Perox is doubled =2/25= 2*(2/50) Hence the final answer = 2/ 25/100 When perox = 100 = 25*4 Therefore the water = 400 Thanks
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