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# The rectangle A has a by b and another rectangle B has c by d. If a/c=

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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
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The rectangle A has a by b and another rectangle B has c by d. If a/c=  [#permalink]

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Updated on: 04 Apr 2016, 06:06
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Question Stats:

93% (01:22) correct 7% (03:12) wrong based on 48 sessions

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The rectangle A has a(width) and b(height) and another rectangle B has c(width) and d(height). If a/c=b/d=3/2, what is the ratio of the rectangle A’s area to the rectangle B’s?

A. 3/2
B. 3/4
C. 9/2
D. 9/4
E. 27/8

* A solution will be posted in two days.

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"Only $79 for 1 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Originally posted by MathRevolution on 03 Apr 2016, 03:08. Last edited by MathRevolution on 04 Apr 2016, 06:06, edited 1 time in total. Math Expert Joined: 02 Aug 2009 Posts: 7956 Re: The rectangle A has a by b and another rectangle B has c by d. If a/c= [#permalink] ### Show Tags 03 Apr 2016, 03:23 MathRevolution wrote: The rectangle A has a by b and another rectangle B has c by d. If a/c=b/d=3/2, what is the ratio of the rectangle A’s area to the rectangle B’s? A. 3/2 B. 3/4 C. 9/2 D. 9/4 E. 27/8 * A solution will be posted in two days. Hi, I am sure by 'The rectangle A has a by b ', you mean rectangle has sides a and b.. the ratio of legth and breadth of both the rectangles is 3/2.. so the area will be in the ratio $$\frac{3^2}{2^2}=\frac{9}{4}$$ D _________________ CEO Status: GMATINSIGHT Tutor Joined: 08 Jul 2010 Posts: 2977 Location: India GMAT: INSIGHT Schools: Darden '21 WE: Education (Education) Re: The rectangle A has a by b and another rectangle B has c by d. If a/c= [#permalink] ### Show Tags 03 Apr 2016, 06:15 MathRevolution wrote: The rectangle A has a by b and another rectangle B has c by d. If a/c=b/d=3/2, what is the ratio of the rectangle A’s area to the rectangle B’s? A. 3/2 B. 3/4 C. 9/2 D. 9/4 E. 27/8 * A solution will be posted in two days. "The rectangle A has a by b and another rectangle B has c by d" I find it NON-GMAT LANGUAGE a/c=b/d=3/2 i.e. a/b = c/d i.e. the two rectangles are similar rectangles Ratio of Areas = Square of ratio of their corresponding sides i.e. Ratio of Areas of Rectangle A and B = (a/c)^2 = (3/2)^2 = 9/4 ANswer: Option D _________________ Prosper!!! GMATinsight Bhoopendra Singh and Dr.Sushma Jha e-mail: info@GMATinsight.com I Call us : +91-9999687183 / 9891333772 Online One-on-One Skype based classes and Classroom Coaching in South and West Delhi http://www.GMATinsight.com/testimonials.html ACCESS FREE GMAT TESTS HERE:22 ONLINE FREE (FULL LENGTH) GMAT CAT (PRACTICE TESTS) LINK COLLECTION Current Student Joined: 12 Aug 2015 Posts: 2569 Schools: Boston U '20 (M) GRE 1: Q169 V154 Re: The rectangle A has a by b and another rectangle B has c by d. If a/c= [#permalink] ### Show Tags 03 Apr 2016, 12:58 Quick Question sir .. Does a by b means length =a and breadth =b if so the answer is D _________________ Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 8011 GMAT 1: 760 Q51 V42 GPA: 3.82 Re: The rectangle A has a by b and another rectangle B has c by d. If a/c= [#permalink] ### Show Tags 04 Apr 2016, 06:05 GMATinsight wrote: MathRevolution wrote: The rectangle A has a by b and another rectangle B has c by d. If a/c=b/d=3/2, what is the ratio of the rectangle A’s area to the rectangle B’s? A. 3/2 B. 3/4 C. 9/2 D. 9/4 E. 27/8 * A solution will be posted in two days. "The rectangle A has a by b and another rectangle B has c by d" I find it NON-GMAT LANGUAGE a/c=b/d=3/2 i.e. a/b = c/d i.e. the two rectangles are similar rectangles Ratio of Areas = Square of ratio of their corresponding sides i.e. Ratio of Areas of Rectangle A and B = (a/c)^2 = (3/2)^2 = 9/4 ANswer: Option D Sorry about the mistake. I have revised the question. _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$79 for 1 month Online Course"
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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 8011
GMAT 1: 760 Q51 V42
GPA: 3.82
Re: The rectangle A has a by b and another rectangle B has c by d. If a/c=  [#permalink]

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05 Apr 2016, 06:01
The rectangle A has a(width) and b(height) and another rectangle B has c(width) and d(height). If a/c=b/d=3/2, what is the ratio of the rectangle A’s area to the rectangle B’s?

A. 3/2
B. 3/4
C. 9/2
D. 9/4
E. 27/8

-> a=3k, c=2, and b=3m, d=2m
Then, the ratio of the area is (3k)(3m):(2k)(2m)=9km:4km=9:4=9/4
Hence, the answer is D.
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MathRevolution: Finish GMAT Quant Section with 10 minutes to spare
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Re: The rectangle A has a by b and another rectangle B has c by d. If a/c=  [#permalink]

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19 Mar 2018, 06:45
MathRevolution wrote:
The rectangle A has a(width) and b(height) and another rectangle B has c(width) and d(height). If a/c=b/d=3/2, what is the ratio of the rectangle A’s area to the rectangle B’s?

A. 3/2
B. 3/4
C. 9/2
D. 9/4
E. 27/8

We can let a = b = 12.

We can let c = d = 8.

The area of rectangle A is 12 x 12 = 144.

The area of rectangle B is 8 x 8 = 64.

The ratio of the area of rectangle A to that of rectangle B is:

144/64 = 18/8 = 9/4

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Re: The rectangle A has a by b and another rectangle B has c by d. If a/c=   [#permalink] 19 Mar 2018, 06:45
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