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The rectangle A has a by b and another rectangle B has c by d. If a/c=

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Math Revolution GMAT Instructor
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The rectangle A has a by b and another rectangle B has c by d. If a/c=  [#permalink]

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New post Updated on: 04 Apr 2016, 06:06
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The rectangle A has a(width) and b(height) and another rectangle B has c(width) and d(height). If a/c=b/d=3/2, what is the ratio of the rectangle A’s area to the rectangle B’s?

A. 3/2
B. 3/4
C. 9/2
D. 9/4
E. 27/8


* A solution will be posted in two days.

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Originally posted by MathRevolution on 03 Apr 2016, 03:08.
Last edited by MathRevolution on 04 Apr 2016, 06:06, edited 1 time in total.
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Re: The rectangle A has a by b and another rectangle B has c by d. If a/c=  [#permalink]

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New post 03 Apr 2016, 03:23
MathRevolution wrote:
The rectangle A has a by b and another rectangle B has c by d. If a/c=b/d=3/2, what is the ratio of the rectangle A’s area to the rectangle B’s?

A. 3/2
B. 3/4
C. 9/2
D. 9/4
E. 27/8


* A solution will be posted in two days.


Hi,
I am sure by 'The rectangle A has a by b ', you mean rectangle has sides a and b..
the ratio of legth and breadth of both the rectangles is 3/2..
so the area will be in the ratio \(\frac{3^2}{2^2}=\frac{9}{4}\)
D
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Re: The rectangle A has a by b and another rectangle B has c by d. If a/c=  [#permalink]

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New post 03 Apr 2016, 06:15
MathRevolution wrote:
The rectangle A has a by b and another rectangle B has c by d. If a/c=b/d=3/2, what is the ratio of the rectangle A’s area to the rectangle B’s?

A. 3/2
B. 3/4
C. 9/2
D. 9/4
E. 27/8


* A solution will be posted in two days.


"The rectangle A has a by b and another rectangle B has c by d"
I find it NON-GMAT LANGUAGE


a/c=b/d=3/2

i.e. a/b = c/d i.e. the two rectangles are similar rectangles

Ratio of Areas = Square of ratio of their corresponding sides

i.e. Ratio of Areas of Rectangle A and B = (a/c)^2 = (3/2)^2 = 9/4

ANswer: Option D
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Re: The rectangle A has a by b and another rectangle B has c by d. If a/c=  [#permalink]

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New post 03 Apr 2016, 12:58
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Re: The rectangle A has a by b and another rectangle B has c by d. If a/c=  [#permalink]

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New post 04 Apr 2016, 06:05
GMATinsight wrote:
MathRevolution wrote:
The rectangle A has a by b and another rectangle B has c by d. If a/c=b/d=3/2, what is the ratio of the rectangle A’s area to the rectangle B’s?

A. 3/2
B. 3/4
C. 9/2
D. 9/4
E. 27/8


* A solution will be posted in two days.


"The rectangle A has a by b and another rectangle B has c by d"
I find it NON-GMAT LANGUAGE


a/c=b/d=3/2

i.e. a/b = c/d i.e. the two rectangles are similar rectangles

Ratio of Areas = Square of ratio of their corresponding sides

i.e. Ratio of Areas of Rectangle A and B = (a/c)^2 = (3/2)^2 = 9/4

ANswer: Option D


Sorry about the mistake. I have revised the question.
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Math Revolution GMAT Instructor
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Re: The rectangle A has a by b and another rectangle B has c by d. If a/c=  [#permalink]

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New post 05 Apr 2016, 06:01
The rectangle A has a(width) and b(height) and another rectangle B has c(width) and d(height). If a/c=b/d=3/2, what is the ratio of the rectangle A’s area to the rectangle B’s?

A. 3/2
B. 3/4
C. 9/2
D. 9/4
E. 27/8


-> a=3k, c=2, and b=3m, d=2m
Then, the ratio of the area is (3k)(3m):(2k)(2m)=9km:4km=9:4=9/4
Hence, the answer is D.
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Re: The rectangle A has a by b and another rectangle B has c by d. If a/c=  [#permalink]

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New post 19 Mar 2018, 06:45
MathRevolution wrote:
The rectangle A has a(width) and b(height) and another rectangle B has c(width) and d(height). If a/c=b/d=3/2, what is the ratio of the rectangle A’s area to the rectangle B’s?

A. 3/2
B. 3/4
C. 9/2
D. 9/4
E. 27/8


We can let a = b = 12.

We can let c = d = 8.

The area of rectangle A is 12 x 12 = 144.

The area of rectangle B is 8 x 8 = 64.

The ratio of the area of rectangle A to that of rectangle B is:

144/64 = 18/8 = 9/4

Answer: D
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Re: The rectangle A has a by b and another rectangle B has c by d. If a/c= &nbs [#permalink] 19 Mar 2018, 06:45
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