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The sides of rectangle X are each multiplied by a to form re

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The sides of rectangle X are each multiplied by a to form re  [#permalink]

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New post 27 Feb 2014, 13:50
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The sides of rectangle X are each multiplied by a to form rectangle Y and by b to form rectangle Z. a times the area of X is 10, and b times the area of X is 5. If the difference in area between Y and Z is 300, what is a - b?

A. 5
B. 20
C. 30
D. 50
E. 60

Set sides of rectangle X are L and W
Area of X: = LW Area of Y = (aL)(aW) = a^2 * LW Area of Z = (bL)(bW) = b^2 * LW a times area X = aLW = 10 b times area X = bLW = 5
Which means that difference between Y and Z = aaLW – bbLW = 300.
And since you're looking to solve for a - b, you can try to get a and b alone by factoring out the common LW terms:
LW(a^2 - b^2) = 300
Which gives you the Difference of Squares setup that allows you to get (a - b) alone:
LW(a + b)(a - b) = 300
Then you should see that if you distribute LW across the first set of parentheses, you can get aLW and bLW, for which you have actual values:
(aLW + bLW)(a - b) = 300
(10 + 5)(a - b) = 300 15(a - b) = 300 (a - b) = 20


Hi, I want to know if we have the simpler solution, please
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Re: The sides of rectangle X are each multiplied by a to form re  [#permalink]

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New post 27 Feb 2014, 21:35
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goodyear2013 wrote:
The sides of rectangle X are each multiplied by a to form rectangle Y and by b to form rectangle Z. a times the area of X is 10, and b times the area of X is 5. If the difference in area between Y and Z is 300, what is a - b?
5
20
30
50
60

Set sides of rectangle X are L and W
Area of X: = LW Area of Y = (aL)(aW) = a^2 * LW Area of Z = (bL)(bW) = b^2 * LW a times area X = aLW = 10 b times area X = bLW = 5
Which means that difference between Y and Z = aaLW – bbLW = 300.
And since you're looking to solve for a - b, you can try to get a and b alone by factoring out the common LW terms:
LW(a^2 - b^2) = 300
Which gives you the Difference of Squares setup that allows you to get (a - b) alone:
LW(a + b)(a - b) = 300
Then you should see that if you distribute LW across the first set of parentheses, you can get aLW and bLW, for which you have actual values:
(aLW + bLW)(a - b) = 300
(10 + 5)(a - b) = 300 15(a - b) = 300 (a - b) = 20


Hi, I want to know if we have the simpler solution, please


Assume the side of rectangle X is s.

X (side s, area s^2)
Y (side as, area (as)^2)
Z (side bs, area (bs)^2)

Given: \(as^2 = 10\), \(bs^2 = 5\) ..........(I)
\((as)^2 - (bs)^2 = 300\)
\(s^2 (a+b)(a-b) = 300\) ...........(II)

We need to find (a-b).
From (I), \(as^2 + bs^2 = 15 = s^2(a+b)\) (you do this because you need to get rid of s^2 and (a+b) in equation (II) above)
Substitute this in (II) to get \(15*(a-b) = 300\)
(a-b) = 20
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Re: The sides of rectangle X are each multiplied by a to form re  [#permalink]

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New post 28 Feb 2014, 00:02
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VeritasPrepKarishma wrote:
goodyear2013 wrote:
The sides of rectangle X are each multiplied by a to form rectangle Y and by b to form rectangle Z. a times the area of X is 10, and b times the area of X is 5. If the difference in area between Y and Z is 300, what is a - b?
5
20
30
50
60

Set sides of rectangle X are L and W
Area of X: = LW Area of Y = (aL)(aW) = a^2 * LW Area of Z = (bL)(bW) = b^2 * LW a times area X = aLW = 10 b times area X = bLW = 5
Which means that difference between Y and Z = aaLW – bbLW = 300.
And since you're looking to solve for a - b, you can try to get a and b alone by factoring out the common LW terms:
LW(a^2 - b^2) = 300
Which gives you the Difference of Squares setup that allows you to get (a - b) alone:
LW(a + b)(a - b) = 300
Then you should see that if you distribute LW across the first set of parentheses, you can get aLW and bLW, for which you have actual values:
(aLW + bLW)(a - b) = 300
(10 + 5)(a - b) = 300 15(a - b) = 300 (a - b) = 20


Hi, I want to know if we have the simpler solution, please


Assume the side of rectangle X is s.

X (side s, area s^2)
Y (side as, area (as)^2)
Z (side bs, area (bs)^2)

Given: \(as^2 = 10\), \(bs^2 = 5\) ..........(I)
\((as)^2 - (bs)^2 = 300\)
\(s^2 (a+b)(a-b) = 300\) ...........(II)

We need to find (a-b).
From (I), \(as^2 + bs^2 = 15 = s^2(a+b)\) (you do this because you need to get rid of s^2 and (a+b) in equation (II) above)
Substitute this in (II) to get \(15*(a-b) = 300\)
(a-b) = 20


Did you consider a rectangle as a square? Because if it is a rectangle then the sides may or may not be equal. Please clarify.
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Re: The sides of rectangle X are each multiplied by a to form re  [#permalink]

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New post 28 Feb 2014, 02:23
Every square is a rectangle however every rectangle need not be a square.
Considering the same, the answer comes up correct = 20 = Answer = B

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Re: The sides of rectangle X are each multiplied by a to form re  [#permalink]

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New post 28 Feb 2014, 07:56
it doesn't matter here if its a square o rectanlge value gets replaced later. take it as s^2 or a*b
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Re: The sides of rectangle X are each multiplied by a to form re  [#permalink]

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New post 28 Feb 2014, 10:54
b2bt wrote:
it doesn't matter here if its a square o rectanlge value gets replaced later. take it as s^2 or a*b

Agreed, it gets cancelled, sorry for the trouble :oops:
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Re: The sides of rectangle X are each multiplied by a to form re  [#permalink]

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New post 01 Mar 2014, 19:41
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Fantabulous wrote:
Did you consider a rectangle as a square? Because if it is a rectangle then the sides may or may not be equal. Please clarify.


I have assumed that the rectangle is a square since square is also a type of rectangle (but I see I missed writing it).
It is a PS question so it will have a unique answer. This means a - b will be the same for every such group of rectangles. So we can easily take one such group such that the rectangles are squares to make our calculations easier.
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Re: The sides of rectangle X are each multiplied by a to form re  [#permalink]

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New post 27 Apr 2015, 19:32
Could you please let me know why you do not distribute the s^2 through the parenthesis? I asked this in my own topic but it has since been locked and no further information was provided to me except to link to this thread.

\(s^2(a+b)(a−b)=300\) ...........(II)

Why does this not simplify to:
\(15∗s^2a−s^2b)\)

veritas-prep-the-sides-of-rectangle-x-are-each-multiplied-by-a-to-for-196927.html
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Re: The sides of rectangle X are each multiplied by a to form re  [#permalink]

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New post 27 Apr 2015, 20:30
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willowtree2 wrote:
Could you please let me know why you do not distribute the s^2 through the parenthesis? I asked this in my own topic but it has since been locked and no further information was provided to me except to link to this thread.

\(s^2(a+b)(a−b)=300\) ...........(II)

Why does this not simplify to:
\(15∗s^2a−s^2b)\)

veritas-prep-the-sides-of-rectangle-x-are-each-multiplied-by-a-to-for-196927.html


\((a+b)*(a-b) = a^2 - b^2\)
You can simplify this to \(s^2a^2 - s^2b^2 = 300\) but how will that take you to the answer? You need the value of \((a - b)\) so you need to get rid of only \(s^2(a+b)\).
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Re: The sides of rectangle X are each multiplied by a to form re  [#permalink]

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New post 04 Sep 2017, 03:57
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Let rectangle X length=l width=w => Area = l*w
So now: rectangle Y length=a*l width=a*w => Area =a^2* l*w
rectangle Z length=b*l width=b*w => Area =b^2* l*w

given: a* Area of X = 10 = a*l*w
b* Area of X = 5 = b*l*w

so we can write a*l*w+b*l*w=10+5
=> l*w(a+b)=15

Also given => Area of Y - area of Z = 300 = a^2*l*w -b^2*l*w

so lw(a^2-b^2)=300
=> l*w(a+b)(a-b)=300
=> 15 (a-b)=300
=> (a-b)= 20


Answer: B
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Re: The sides of rectangle X are each multiplied by a to form re  [#permalink]

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New post 14 Nov 2017, 05:11
VeritasPrepKarishma wrote:
goodyear2013 wrote:
The sides of rectangle X are each multiplied by a to form rectangle Y and by b to form rectangle Z. a times the area of X is 10, and b times the area of X is 5. If the difference in area between Y and Z is 300, what is a - b?
5
20
30
50
60

Set sides of rectangle X are L and W
Area of X: = LW Area of Y = (aL)(aW) = a^2 * LW Area of Z = (bL)(bW) = b^2 * LW a times area X = aLW = 10 b times area X = bLW = 5
Which means that difference between Y and Z = aaLW – bbLW = 300.
And since you're looking to solve for a - b, you can try to get a and b alone by factoring out the common LW terms:
LW(a^2 - b^2) = 300
Which gives you the Difference of Squares setup that allows you to get (a - b) alone:
LW(a + b)(a - b) = 300
Then you should see that if you distribute LW across the first set of parentheses, you can get aLW and bLW, for which you have actual values:
(aLW + bLW)(a - b) = 300
(10 + 5)(a - b) = 300 15(a - b) = 300 (a - b) = 20


Hi, I want to know if we have the simpler solution, please


Assume the side of rectangle X is s.

X (side s, area s^2)
Y (side as, area (as)^2)
Z (side bs, area (bs)^2)

Given: \(as^2 = 10\), \(bs^2 = 5\) ..........(I)
\((as)^2 - (bs)^2 = 300\)
\(s^2 (a+b)(a-b) = 300\) ...........(II)

We need to find (a-b).
From (I), \(as^2 + bs^2 = 15 = s^2(a+b)\) (you do this because you need to get rid of s^2 and (a+b) in equation (II) above)
Substitute this in (II) to get \(15*(a-b) = 300\)
(a-b) = 20


Another way of doing this..

Let the original sides be x and y ---- area = \(xy\)

For Rectangle X -- ax and ay ---- area = \(a^2xy\)

For Rectangle Y -- bx an by ---- area = \(b^2xy\)

Now, it's given that

\(axy = 10\)
Thus
\(a = \frac{10}{(xy)}\)

Similarly we can write for Z as

\(bxy = 5\)
Thus
\(b = \frac{5}{(xy)}\)

It can clearly be seen that

\(a = 2b\)

Substituting "axy" in the original area equation..we can see that the area of X can be written as = 10a
Similarly for B it can be written as = 5b

Difference in areas

\(10a - 5b = 300\)

Using value of a as 2b, we get

b = 20
a = 40
Thus
a-b = 20
(B)
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