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Bunuel
The sum of 8 numbers is 168. If one of the numbers is 28, what is the average of the other 7 numbers?

A. 17
B. 18
C. 19
D. 20
E. 21

sum of 8 = 168
sum of 7 = 168-28= 140
avg of 7 ; 140/7; 20
IMO D
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Bunuel
The sum of 8 numbers is 168. If one of the numbers is 28, what is the average of the other 7 numbers?

A. 17
B. 18
C. 19
D. 20
E. 21

Let the sum of \(7\) numbers be \(= x\)

\(28 + x = 168\)

\(x =168 - 28 = 140\)

Average of \(7\) numbers \(= \frac{140}{7} = 20\)

Answer D
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Bunuel
The sum of 8 numbers is 168. If one of the numbers is 28, what is the average of the other 7 numbers?

A. 17
B. 18
C. 19
D. 20
E. 21

Sum of 7 numbers = 168 - 28 = 140
—> Average = 140/7 = 20

Option D

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Bunuel
The sum of 8 numbers is 168. If one of the numbers is 28, what is the average of the other 7 numbers?

A. 17
B. 18
C. 19
D. 20
E. 21

Since the sum of the 8 numbers is 168, the sum of the remaining 7 numbers, after excluding 28, is 168 - 28 = 140. Thus, the average of the other 7 numbers is (168 - 28)/7 = 140/7 = 20.

Answer: D
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