Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 1508:30 AM PDT
-09:30 AM PDT
Struggling with Boldface or Paradox questions in GMAT Critical Reasoning (CR)? Boldface and Paradox CR questions are often overlooked amidst the other more common GMAT CR question types. But mastering these can significantly boost your Verbal score.- May 15
10:00 AM PDT
-11:00 AM PDT
Struggling to finish the GMAT on time? You’re not alone. The #1 reason students score lower than expected on the GMAT isn’t lack of knowledge or silly mistakes—it’s running out of time. - May 14
10:00 AM PDT
-11:00 AM PDT
GMAT Verbal Practice question quiz. Solve 20 GMAT Focus practice questions written by GMAT Ninja. Take this GMAT practice test live with peers in timed conditions, analyze your GMAT study progress, and see where you stand in the GMAT student pool. 
May 1411:30 AM EDT
-12:30 PM EDT
Is INSEAD your dream b-school and you're looking for solid prep and application strategies to get there? Check out Barkavi’s end-to-end journey to know how she did! Get insights into the INSEAD admissions process, know what Adcoms look at, and more!
May 1609:00 PM PDT
-10:00 PM PDT
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
May 1706:30 AM PDT
-08:30 AM PDT
We know Strengthen and Weaken questions account for more than 50% of the CR questions on the GMAT. With CR becoming even more important on GMAT Focus, it's time you strengthen your weaknesses with an approach that improves your solving time and accuracy!
May 1711:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.- May 18
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. - Jun 10
06:00 AM PDT
-05:30 PM PDT
Register for the GMAT Club Virtual MBA Spotlight fair, the biggest MBA fair of the year. You will have a chance to hear Admissions directors from almost every Top 20 program speak, network with peers, and conveniently attend morning or afternoon sessions.
23 Jul 2010, 05:52
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
66% (01:23) correct
34%
(01:36)
wrong
based on 897
sessions
History
Date
Time
Result
Not Attempted Yet
The table shows the results of a poll which asked drivers how many accidents they had had over the previous 5 years. What is the median number of accidents per driver?
A. 0.5
B. 1
C. 1.5
D. 2
E. 4
Attachment:
p006-9.gif [ 1.03 KiB | Viewed 30560 times ]
27 Sep 2010, 08:10
Kudos
Bookmarks
anaik100
The table shows the results of a poll which asked drivers how many accidents they had had over the previous 5 years. What is the median number of accidents per driver?
A. 0.5
B. 1
C. 1.5
D. 2
E. 4
If a set has odd number of terms the median of a set is the middle number when arranged in ascending or descending order;
If a set has even number of terms the median of a set is the average of the two middle terms when arranged in ascending or descending order.
There are total of \(17+13+21+4+2+2+1=60\) drivers (60 terms) so the median number of accidents per driver would be the average of accidents of 30th and 31st drivers (as we have even # of terms).
30th term equals to 1 and 31st term equals to 2 so \(median=\frac{1+2}{2}\).
Answer: C.
To elaborate more, you can imagine these data points as:
0, ..., 0, 1, ..., 1, 2, ..., 2, 3, ..., 3, 4, ..., 4, 5, ..., 5, 6, ..., 6 --> 17 zeros, 13 ones, 21 twos and so on, total of 60 data points. Median would be the average of 30th and 31st terms: \(median=\frac{1+2}{2}\).
Hope it's clear.
General Discussion
23 Jul 2010, 08:07
Kudos
Bookmarks
i actually messed up the question the first time cause i didn't add correctly. in either case, i got C also.
in order to find the median we must put the values in order from lowest to highest values.
6 5 4 3 2 1 0 = number of accidents
-----------------------------
1 2 2 4 21 13 17 = values representing people
we can now find the median by finding the middle number. there is a total of
1 + 2 + 2 + 4 + 21 + 13 + 17 = 60 people.
middle value will be represented as average in 30th and 31st person.
so 30th person had 2 accidents while 31st person had one. median will thusly be:
2 + 1 / 2 = 1.5
in order to find the median we must put the values in order from lowest to highest values.
6 5 4 3 2 1 0 = number of accidents
-----------------------------
1 2 2 4 21 13 17 = values representing people
we can now find the median by finding the middle number. there is a total of
1 + 2 + 2 + 4 + 21 + 13 + 17 = 60 people.
middle value will be represented as average in 30th and 31st person.
so 30th person had 2 accidents while 31st person had one. median will thusly be:
2 + 1 / 2 = 1.5
