kilukilam
The temperature of a certain cup of coffee 10 minutes after it was poured was 120 degrees Fahrenheit. If the temperature F of the coffee t minutes after it was poured can be determined by the formula F = 120*2^(-at) + 60, where F is in degrees Fahrenheit and a is a constant. Then the temperature of the coffee 30 minutes after it was poured was how many degrees Fahrenheit?
A. 65
B. 75
C. 80
D. 85
E. 90
First we need to find the value of a using F = 120 and t = 10:
120 = 120 * 2^(-10a) + 60
60 = 120 * 2^(-10a)
1/2 = 2^(-10a)
2^(-1) = 2^(-10a)
With a common base, we can equate the exponents:
-1 = -10a
a = 1/10
Now we can find F using a = 1/10 and t = 30:
F = 120 * 2^(-(1/10)(30)) + 60
F = 120 * 2^(-3) + 60
F = 120 * 1/8 + 60
F = 15 + 60
F = 75
Answer: 2/B
, If we cancel out 120 at this stage, I'm not sure how to proceed next? Could you help? Thanks