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# The Tigers beat the Sharks 2 out of the first 3 times they played. The

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Senior Manager
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Joined: 02 Nov 2018
Posts: 280
The Tigers beat the Sharks 2 out of the first 3 times they played. The  [#permalink]

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18 Mar 2019, 10:02
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Difficulty:

55% (hard)

Question Stats:

55% (02:11) correct 45% (02:24) wrong based on 29 sessions

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The Tigers beat the Sharks 2 out of the first 3 times they played. They then played N more times, and the Sharks ended up winning at least 95% of all the games played. What is the minimum possible value for N?

(A) 35
(B) 37
(C) 39
(D) 41
(E) 43
Manager
Joined: 05 Oct 2017
Posts: 100
Location: India
Schools: ISB '21, IIMA , IIMB
GPA: 4
WE: Analyst (Energy and Utilities)
Re: The Tigers beat the Sharks 2 out of the first 3 times they played. The  [#permalink]

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18 Mar 2019, 10:38
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The Tigers beat the Sharks 2 out of the first 3 times they played. They then played N more times, and the Sharks ended up winning at least 95% of all the games played. What is the minimum possible value for N?

(A) 35
(B) 37
(C) 39
(D) 41
(E) 43

Currently the winning percent of Sharks is 1/3*100= 33.33 %.Since we have to find the minimum possible value of N for which Shark's winning percentage becomes at least 95% . So sharks has to win all the N matches so that N is minimized.

Hence total matches = N+3. When shark will have winning percent of 95% then that of tigers will be 5%. And they will win only total of 2 matches

So 2 matches correspond to 5% of the total matches.
Therefore total number of matches = 2/5*100 = 40.

So N+3 = 40 => N= 37

Alternatively, you can solve the following equation and find the answer .

2/(N+3) = 5/100

Solving you will get N = 37. Hence B)
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Joined: 07 May 2019
Posts: 466
Location: India
Re: The Tigers beat the Sharks 2 out of the first 3 times they played. The  [#permalink]

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28 Feb 2020, 00:00
1
The Tigers beat the Sharks 2 out of the first 3 times they played. They then played N more times, and the Sharks ended up winning at least 95% of all the games played. What is the minimum possible value for N?

(A) 35
(B) 37
(C) 39
(D) 41
(E) 43

Solution:

• Tiger beats sharks in 2 out of the first 3 matches.
• Sharks ended up winning at least $$95\%$$ matches
o Sharks lose at most $$5\%$$ match
• Now, total matches = $$N+3$$
o For the minimum number of matches, we can assume that sharks lost only 2 matches
• By above inferences
o $$2 ≤ 5\%\ of\ (N+3)$$
o $$2 ≤\frac{5}{100}*(N+3)$$
o $$2 ≤ \frac{1}{20}*(N+3)$$
o $$40 ≤ N+3$$
o $$40-3 ≤ N$$
o $$37 ≤ N$$
• The minimum possible value of N is 37.
Hence, the correct answer is Option B.
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Intern
Joined: 25 Oct 2019
Posts: 21
Re: The Tigers beat the Sharks 2 out of the first 3 times they played. The  [#permalink]

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28 Feb 2020, 00:32
1
total game played among them= N+3

game won by sharks = N+3-2

(because we have to minimize the total no. of games....so assume that all other games were won by sharks...)

given...N+1/N+3 * 100 = 95

N= 37..

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Intern
Joined: 05 Jan 2020
Posts: 11
Re: The Tigers beat the Sharks 2 out of the first 3 times they played. The  [#permalink]

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28 Feb 2020, 00:46
Initial 3 matches, tiger wins 2 and shark wins 1, so if they play n more matches
Total matches =n+3
As we have to consider minimum value it is possible when shark losses no further match
So lost match by shark = 2 which is 5% of total matches played
I.e. 2=5%x (X is total matches played n+3)
=40
N=37

Posted from my mobile device
Re: The Tigers beat the Sharks 2 out of the first 3 times they played. The   [#permalink] 28 Feb 2020, 00:46
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