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505-555 Level|   Geometry|            
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thangvietnam
we do not have to remember the formular for volume and surface area of a ball. is that right?

that is good

As far as I know, we do not have to remember it. Economist also supports that:

"If you find these formulas hard to remember, don't sweat it. If a sphere is tested in the GMAT, the problem always supplies the relevant formula."
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r^3 = 972*3/4 = 729.
so, r = 9.
Surface area = 4(pi)(9)^2 = 324 (pi). Ans (D).
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We need the radius (r) of the sphere, to form the answer to the question posed.

They tell us that the volume of the sphere is 972π

So 4/3πrexp3 = 972π, we simplify the πs on both sides, we get:
4/3rexp3 = 972

Then: rexp3 = (3 x 972)/4

rexp3 = (3 x 972)/4

rexp3 = (3 x 243 x 4)/4

Simplifying the 4, we have

rexp3 = 3 x 243

rexp3 = 3 x 3 x 81

rexp3 = 9 x 9exp2

rexp3 = 9exp3

then r = 9

So the surface of the sphere is:

4πrexp2, substituting r = 9, we have

4π9exp2 = 4π81 = 324π

Answer D
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Hi all !
Lets see how we can solve this without a lot of calculations :)

Spherical balloon has a volume of 972π.
So we have the value of 4/3π\(r^3 \)

4/3 π \(r^3\) = 972 π

At this stage, you can factor out and cancel the π from both sides of the equation.
Also, factor out 972 with 4 so that we have
1/3 * (\(r^3\)) = 243
=> \(r^3\) = 3 * 243 = 3* \(3^5\) = \(3^6\)
=> r = \(3^2\)
I will keep the radius as an exponent since we are going to deal with radius again as \(r^2\) for the surface area.
I would like to see if I could use any exponent laws while computation to make it easier.

Now we get to the surface area which is 4 π \(r^2\) computation
I usually try to factor or factor and multiply in the last step with the questions-

So 4 π \(r^2\) = 4 π \((3^2)^2\)

The correct answer has to contain a π and a unit digit of 4*\(3^4\) which is 4*1 or 4
The only such answer choice is D. :thumbsup:

Hope you are clear !

Devmitra Sen
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are we really expected to know that 9^3 = 729?
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