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Bunuel
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Bunuel
There are 5 semi-finalist, including John and Maria. If there is no ties, what is the probability that Maria gets a better position than John?

A. \(\frac{1}{6}\)

B. \(\frac{1}{3}\)

C. \(\frac{1}{2}\)

D. \(\frac{2}{3}\)

E. \(\frac{5}{6}\)
Maria and John can finish in either order:

a. Maria ahead of John
b. John ahead of Maria

Since there are no ties, these two cases are equally likely.

So the probability that Maria gets a better position than John is 1/2.

Answer: C.
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Think like there are five spots for ranking in the order: 1, 2, 3, 4, 5.

Let's say we put Maria at 1 then we can put John at one of 2,3,4,5. Other 3 players can be arranged in 3! ways. Total ways = 4*3!
If we put Maria at 2 then we can put John at one of 3,4,5. Other 3 players can still be arranged in 3! ways. Total ways = 3*3!

Similarly, we will have 2 more cases.

Total number of arrangements = 5!

Probability = 3!*(4+3+2+1)/5! = 1/2


Axwe7
Is there a mathematical explanation for the answer? Bunuel
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Among all possible rankings of the 5 semifinalists, John and Maria can be ordered in only two ways:
  1. Maria finishes ahead of John.
  2. John finishes ahead of Maria.
Since there are no ties and neither person has any advantage over the other, these two outcomes are equally likely.
Therefore, the probability that Maria gets a better position than John is:
1/2

Answer: C

Bunuel
There are 5 semi-finalist, including John and Maria. If there is no ties, what is the probability that Maria gets a better position than John?

A. \(\frac{1}{6}\)

B. \(\frac{1}{3}\)

C. \(\frac{1}{2}\)

D. \(\frac{2}{3}\)

E. \(\frac{5}{6}\)




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Ctrl+C and Ctrl+V seem to have skipped the "Read the Question" step.:lol:
BongBideshini
Total balls: 11
Total ways to draw 2 balls: 11C2 = 55

Favorable cases:
Two red: 5C2 = 10
Two green: 4C2 = 6
Two blue: 2C2 = 1

Total favorable ways:
10 + 6 + 1 = 17

Probability:
17/55

Answer: C


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You've copy pasted so hard that even the question is confused.
BongBideshini
Total balls: 11
Total ways to draw 2 balls: 11C2 = 55

Favorable cases:
Two red: 5C2 = 10
Two green: 4C2 = 6
Two blue: 2C2 = 1

Total favorable ways:
10 + 6 + 1 = 17

Probability:
17/55

Answer: C


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paragw
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And arrived at the wrong address.:sleep:
ankushsambare
You've copy pasted so hard that even the question is confused.

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