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There are two tanks A, B. After 100 litres of water

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Joined: 03 Mar 2018
Posts: 170
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There are two tanks A, B. After 100 litres of water [#permalink]

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New post 06 Mar 2018, 04:16
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A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

66% (01:30) correct 34% (01:44) wrong based on 74 sessions

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There are two tanks A, B. After 100 litres of water got drained from tank A and moved to to tank B, the volume of water in tank B increased by 20 percent. What was the original volume of water in tank A?

1) Before the 100 litres were drained and moved, the sum of the volume of water in the two tanks was 900 litres.
2) After the 100 litres were drained and moved, the volume of water left in tank A was half the volume of water in tank B.

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Re: There are two tanks A, B. After 100 litres of water [#permalink]

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New post 06 Mar 2018, 09:04
1
1
Let, volume of water in tank A and B be V_a and V_b respectively. Given : 100 = (20/100)* V_b

Thus, V_b = 500 litres

Statement 1 : V_a + V_b = 900
Also, V_b = 500. Thus, V_a = 400.

Sufficient.

Statement 2 : After V_b = 500 + 100 = 600

V_a' = (1/2) V_b' = (1/2)* 600 = 300

V_a' = 300 + 100 = 400

Sufficient.

Thus, both statements are alone sufficient to answer the question.

I go with D.

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Re: There are two tanks A, B. After 100 litres of water [#permalink]

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New post 19 Mar 2018, 13:22

SOLUTION



We are given:
    • After \(100\) litres of water is moved from tank A to tank B, the volume of water in tank B is increased by \(20\) percent.

Let us assume:
    • The volume of water in tank A= x litres
    • The Volume of water in tank B =y litres.

Thus,
    • \(\frac{20}{100}\)\(*y\)=\(100\)
    • \(y=500\)

We need to find:
    • What is the value of \(x\)?

Statement-1: “Before the \(100\) litres were drained and moved, the sum of the volume of water in the two tanks was \(900\)litres”.

    • \(x + y= 900\)
    • \(x = 400\) litres

Thus, statement 1 alone is sufficient to answer the question.

Statement-2: “After the \(100\)litres were drained and moved, the volume of water left in tank A was half the volume of water in tank B”.
    • \(x-100\)= \(\frac{1}{2}\)* (y+100)
    • \(2x-200\)= \(500+100\)
    • \(2x=800\)
    • \(x=400\)

Thus, statement 2 alone is sufficient to answer the question.

We can find the answer by each of the statement alone.
Answer: D
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Re: There are two tanks A, B. After 100 litres of water   [#permalink] 19 Mar 2018, 13:22
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