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Re: There is a sequence of r, t, s, 1, 4, 3, 8, 15, 26. Each number of the
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08 Aug 2017, 20:02
MathRevolution wrote:
There is a sequence of r, t, s, 1, 4, 3, 8, 15, 26. Each number of the sequence is the sum of the 3 previous numbers. r=?
A. -2 B. -1 C. 0 D. 1 E. 2
This sequence is possible when r = -2, s = 5, t = -2 as r+s+t = 1. To double check whether the numbers we have selected are correct, we also have s + t + 1 = 4 to prove that the numbers chosen are correct.
Hence, it is clear that Option A(r = -2) is our correct answer.
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