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There is a set of numbers 2, 4, 6, 8,10 and x. What is the value of x? [#permalink]
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15 Sep 2017, 15:12
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There is a set of numbers 2, 4, 6, 8,10 and x. What is the value of x? (1) x is a 2digit positive integer. (2) The average of these integers is equal to the median of these integers.
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Re: There is a set of numbers 2, 4, 6, 8,10 and x. What is the value of x? [#permalink]
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15 Sep 2017, 16:22
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A. This can not determine the value of x. In other word, the value can be 20 or 11. So insufficient.
B. If value of x is lower than 10, it would be necessary to be determined. But if the value of x is equals or higher than 10, it would be determinable. So insufficient.
(1) & (2) says that x is higher than 9. So the value of x is: (2+4+6+8+10+x)/6=7 X=12
Answer is C
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Re: There is a set of numbers 2, 4, 6, 8,10 and x. What is the value of x? [#permalink]
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15 Sep 2017, 20:57
Ans is C.. But a slight trap here in Statement A is: its given two digit integer and with the sequence given in the question, it might lead us to think that x is 12 after 10. Just highlighting a possible trap.



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Re: There is a set of numbers 2, 4, 6, 8,10 and x. What is the value of x? [#permalink]
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15 Sep 2017, 21:05
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Bounce1987 wrote: There is a set of numbers 2, 4, 6, 8,10 and x. What is the value of x?
(1) x is a 2digit positive integer. (2) The average of these integers is equal to the median of these integers. Statement 1: \(x\) can be any two digit no 10,20,30.... etc. Hence InsufficientStatement 2: Average of the set \(=\frac{(2+4+6+8+10+x)}{6}=\frac{(30+x)}{6}=5+\frac{x}{6}\) Median, if \(6<x<8\), then the Median would be \(\frac{6+x}{2}\) but if \(x>8\), then the Median would be \(\frac{6+8}{2} = 7\) Now the two values of median when equated against the average will give two different values of \(x\). Hence InsufficientCombining 1 & 2, we know for sure that \(x>8\) . Therefore \(5+\frac{x}{6}=7\) or \(x =12\) Option C



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Re: There is a set of numbers 2, 4, 6, 8,10 and x. What is the value of x? [#permalink]
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30 Sep 2017, 04:16
Bounce1987 wrote: There is a set of numbers 2, 4, 6, 8,10 and x. What is the value of x?
(1) x is a 2digit positive integer. (2) The average of these integers is equal to the median of these integers. Value base Qs, x=? in set ={2,4,6..x} St1 x is 2 digit positive integer x can be any 2 digit integer insufficient St2 the average is equal to median then consecutive integers x can be 0 or 12,insufficient Combine x can be only 12 sufficient Answer is C



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Re: There is a set of numbers 2, 4, 6, 8,10 and x. What is the value of x? [#permalink]
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18 Oct 2017, 00:08
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I went through with a little easier approach. Please let me know if I am on the right track though. There is a set of numbers 2, 4, 6, 8,10 and x. What is the value of x?
(1) x is a 2digit positive integer. (2) The average of these integers is equal to the median of these integers.
1) According to the first statement, x=11,12,13 or any number. Hence insufficient 2)According to this statement, Average of these integers(mean)=Median The above Statement is possible when the set of integers are consecutive integers x=0,12 Not sufficient 1+2=x=12 Therefore C is the answer



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Re: There is a set of numbers 2, 4, 6, 8,10 and x. What is the value of x? [#permalink]
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30 Jan 2018, 09:07
niks18 wrote: Bounce1987 wrote: There is a set of numbers 2, 4, 6, 8,10 and x. What is the value of x?
(1) x is a 2digit positive integer. (2) The average of these integers is equal to the median of these integers. Statement 1: \(x\) can be any two digit no 10,20,30.... etc. Hence InsufficientStatement 2: Average of the set \(=\frac{(2+4+6+8+10+x)}{6}=\frac{(30+x)}{6}=5+\frac{x}{6}\) Median, if \(6<x<8\), then the Median would be \(\frac{6+x}{2}\) but if \(x>8\), then the Median would be \(\frac{6+8}{2} = 7\) Now the two values of median when equated against the average will give two different values of \(x\). Hence InsufficientCombining 1 & 2, we know for sure that \(x>8\) . Therefore \(5+\frac{x}{6}=7\) or \(x =12\) Option CActually if x is 8 then median is 7 and and average is 6.66.. hence x= 8 does not satisfy the condition , only x= 0, or 6 or 12 satisfy statement 2, since there are 3 values hence insufficient . 1 and 2 combined we have only one two digit integer, 12 hence sufficient.
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Re: There is a set of numbers 2, 4, 6, 8,10 and x. What is the value of x? [#permalink]
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12 Feb 2018, 10:28
Bounce1987 wrote: There is a set of numbers 2, 4, 6, 8,10 and x. What is the value of x?
(1) x is a 2digit positive integer. (2) The average of these integers is equal to the median of these integers. A quick way to solve would be: #1 in itself is insufficient. #2 this statement tells us the set is evenly spaced, so x must either be zero or 12. Now considering statement 1, we can conclude x=12.




Re: There is a set of numbers 2, 4, 6, 8,10 and x. What is the value of x?
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