Bunuel
Tough and Tricky questions: Ratios
Three business partners shared all the proceeds from the sale of their privately held company. If the partner with the largest share received exactly 5/8 of the total proceeds, how much money did the partner with the smallest share receive from the sale?
(1) The partner with the smallest share received from the sale exactly 1/5 the amount received by the partner with the second largest share.
(2) The partner with the second largest share received from the sale exactly half of the two million dollars received by the partner with the largest share.
suppose we have A, B, and C, where A>B>C.
A got 5x/8 where x is the total amount received for the sale of the company
B+C = 3x/8.
1. we are told that C=1/6*3x/8 = x/16. we can not get an answer unless we know the total amount received after sale. so A and D are out.
2. A received 2 mln, B received 1 mln. we know that 2 mln is 5x/8. we can find the X. from x we can subtract 2 mln received by A, and 1 mln received by B. what is left - is for C.
we do not need to solve, but: 2mln=5x/8 => 16 mln = 5x. x=3.2mln.
C got 200k.