AjjayKannan wrote:
Provide solution for the question please
Posted from my mobile device
I hope this is clear enough. Sorry, I'm not an expert at explaining things, but here's how I did it, and no, I do not know how I would do this quickly without a calculator.
First, you need to see how the two ratios relate to each other, so they need to be similar. Change 2:3 to 50:75. Change 25:231 to 50:462.
Now you can clearly see how the water is affecting the solution. So, the difference in water "concentration" from beginning to end is 462-75=387.
Since the process is performed 3 times, divide 387 by 3 to get 129, which is how much is changing per addition of 15lts of water.
Now you are ready to set up the equation. Because water is being added, all ratios in the equation should be in terms of water.
The original mixture is 2:3=4:6, which is 60% water, so the volume of water is 6/10*x where x is the total volume.
The equation becomes 6/10*x + 15lts = 129/
179*(x+15) ; You are adding the original mixture and the 15lts of pure water, and setting it equal to resultant mixture.
Now you solve for x.