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0.1^0+0.1^1+0.1^2+0.1^3=?

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broall
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0.1^0+0.1^1+0.1^2+0.1^3=? [#permalink] New post   09 Apr 2017, 18:40
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96% (00:43) correct 4% (01:14) wrong based on 80 sessions
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\(0.1^0+0.1^1+0.1^2+0.1^3=\)

A. 0.1
B. 1.111
C. 1.1211
D. 1.2341
E. 3.3

Source: GMAT Free
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B
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B
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Re: 0.1^0+0.1^1+0.1^2+0.1^3=? [#permalink] New post   09 Apr 2017, 19:07
nguyendinhtuong wrote:
\(0.1^0+0.1^1+0.1^2+0.1^3=\)

A. 0.1
B. 1.111
C. 1.1211
D. 1.2341
E. 3.3

Source: GMAT Free


I doubt original GMAT will give such simple PS.

However. Only trick here is 0.1 raised to the power 0 is 1 ( For the same reason any number raised to the power 0 is 1)
Once you get that then among B,C,D only B makes sense.
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Re: 0.1^0+0.1^1+0.1^2+0.1^3=? [#permalink] New post   09 Apr 2017, 19:09
nguyendinhtuong wrote:
\(0.1^0+0.1^1+0.1^2+0.1^3=\)

A. 0.1
B. 1.111
C. 1.1211
D. 1.2341
E. 3.3

Source: GMAT Free



= 1 + 1/10 + 1/100 + 1/1000
= 1111/1000
=1.111

Ans B
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0.1^0+0.1^1+0.1^2+0.1^3=? [#permalink] New post   03 May 2017, 06:08
\(.1^0\)+\(.1^1\)+\(.1^2\)+\(.1^3\)

= \((\frac{1}{10})^0\) + .1 + .01 + .001
=\(\frac{1}{1}\) + .111 ---- (since \(1^0\) is 1 and \(10^0\) is 1, hence\(\frac{1}{1}\))
= 1.111 ... Answer B.

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Re: 0.1^0+0.1^1+0.1^2+0.1^3=? [#permalink] New post   06 May 2017, 17:34
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nguyendinhtuong wrote:
\(0.1^0+0.1^1+0.1^2+0.1^3=\)

A. 0.1
B. 1.111
C. 1.1211
D. 1.2341
E. 3.3


Recall that x^0 = 1 for any value of x except 0. Let’s simplify the given expression:

0.1^0 + 0.1^1 + 0.1^2 + 0.1^3

1 + 0.1 + 0.01 + 0.001 = 1.111

Answer: B
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Re: 0.1^0+0.1^1+0.1^2+0.1^3=? [#permalink] New post   20 Sep 2019, 02:06
Expert Reply
broall wrote:
\(0.1^0+0.1^1+0.1^2+0.1^3=\)

A. 0.1
B. 1.111
C. 1.1211
D. 1.2341
E. 3.3

Source: GMAT Free


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Re: 0.1^0+0.1^1+0.1^2+0.1^3=? [#permalink]
20 Sep 2019, 02:06
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