Kritisood
@experts could you explain how we used the midpoint theorem here? :$ how do we know that the north wall is cutting the bedroom side wall at the mid point ?
KritisoodPlease refer ShukhratJon's Solution for your answer.
(According to the mid-point theorem, the line joining the mid-points of two sides of a triangle is parallel to the third side of the triangle. However, note that we are given that line DE is || to AC and lengths of AD = DB = 30. So, we have to apply the concept in a reverse manner.)But i think you can solve the question without applying the similar triangles/midpoint theorem/concept.
Consider the rough diagram below. Consider the triangle △BCF. CE = 15, BF = CF = 30
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Now if ∠ECF = 60° and on joining EF where EF⟂BC, we have right △FEC with ∠EFC = 30°. However, this has to be proved.
(Note that this is about applying reverse concept and its a little time consuming.)In a 30-60-90 right triangle the ratio of sides is \(x:\sqrt{3}x:2x\).
Here, if △BCF is a 30-60-90 right triangle, then sides ratio is CE:EF:CF = 15:EF:30.
Thus, \(EF = 15\sqrt{3}\)
Therefore, with this logic you can prove BE(△BEF) = 15, implying △BCF is an equilateral triangle with side length of 30.
From here onwards the area of an equilateral triangle = \(\frac{\sqrt{3}}{4}*x^2\) where x is the side of the triangle.
Area = \(\frac{\sqrt{3}}{4}*30^2\)
= \(225\sqrt{3}\)
Answer C.