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If the denominator of the fraction, in its reduced form, contains no other prime number facors other than 2 and 5, then the fraction is terminating.

I) \(\frac{83}{80}\)= \(\frac{83}{2^4*5}\)
Denominator contains only 2 and 5 as prime factors, hence \(\frac{83}{80}\) leads to terminating decimal.

II) \(\frac{23}{120}\)= \(\frac{23}{2^3*3*5}\)
Denominator contains 2, 3 and 5 as prime factors, hence \(\frac{23}{120}\) does not lead to terminating decimal.

III)\(\frac{33}{480}\)= \(\frac{3*11}{2^5*3*5}\)=\(\frac{11}{2^5*5}\)
Denominator contains only 2 and 5 as prime factors, hence \(\frac{33}{480}\) leads terminating decimal.

IMO D
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Which of the following fractions will lead to a terminating decimal?

We just simply need to perform division calculations, and see do we have a terminating decimal or not:

I. 83/80
Attachment:
83.PNG
83.PNG [ 5.51 KiB | Viewed 8655 times ]

II. 23/120
Attachment:
230.PNG
230.PNG [ 8.25 KiB | Viewed 8560 times ]

III. 33/480
Attachment:
33.PNG
33.PNG [ 6.63 KiB | Viewed 8532 times ]

If we will test by concept then:

Number will have finite number of integers after decimal of denominator consists of only 2, 5 or both.
I. Has both 2 and 5, so it will terminate
II. Has 2 and 5, but also 3, will not terminate
III. Has only 2 and 5, thus will terminate

A. None
B. I only
C. I and II only

D. I and III only
E. I, II, and III

D is the answer. :heart
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Solution:

General property:
A fraction in its lowest term can be expressed as a terminating decimal if and only if the denominator has powers of only 2 and/or 5.


Lets prime factorize the division.

I. \(\frac{83}{2^4 X 5}\) , Hence we see that the division only contains 2 & 5. So this fraction will be terminating.

II.\(\frac{23}{2^3 X 3 X 5}\)We observe that there is 3 in the prime factorization , Hence this fraction is non terminating

III.\(\frac{33}{480}\)

=\(\frac{{11 X 3}}{2^5 X 3 X 5}\), we observe that 3 gets cancelled with the 3 in the numerator leaving only 2 & 5 as factors in the denominator. Hence this fraction will be terminating.

So the answer here must be D
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For a fraction to have a terminating decimal, its denominator, in the lowest terms, must only have 2 and 5 as prime factors.

83/80 has a denominator of 80, which factors as 2^4 * 5. This satisfies the condition, so it will terminate.

23/120 has a denominator of 120, which factors as 2^3 * 3 * 5. Since 3 is present, this fraction will not terminate.

33/480 simplifies to 11/160, with the denominator 160 as 2^5 * 5. This satisfies the condition, so it will terminate.

Thus, the fractions that lead to a terminating decimal are 83/80 and 33/480.

Answer: D (I and III only)
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