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If x and y are positive integers, is x + y an even integer?

It is possible when either both are even or both are odd

(1) The product of the greatest common factor of x and y and the least common multiple of x and y is even

This implies that x*y=even. However, they could both be even, or even and odd.
Not sufficient


(2) The greatest common factor of x and y is 1

Examples:
Two odds - X=9,y=11 then yes
Odd and even - X=1, y=2 then no
Not suff.
Two evens - impossible


Taking together,
X*y=even and thus we can take the only possible option from the second. It is - odd and even
Thus, thus is sufficient

The answer is C

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If x and y are positive integers, is x + y an even integer?


(1) The product of the greatest common factor of x and y and the least common multiple of x and y is even

(2) The greatest common factor of x and y is 1

Solution:

Statement 1: Insufficient
Test cases:
a. x = 2, y = 3
GCF = 1
LCM = 6

x + y = 5 (odd)

b. x = 4, y = 8
GCF = 4
LCM = 8

x + y = 12 (even)

Statement 2: Insufficient
Test cases:
a. x = 2, y = 3
GCF = 1

x + y = 5 (odd)

b. x = 5, y = 1
GCF = 1

x + y = 6 (even)

Together, since GCF = 1, x + y = odd number based on test case in Statement 1.

The answer is C.
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(1) The product of the greatest common factor of x and y and the least common multiple of x and y is even
Means either LCM or HCf is positive. Not sufficient
(2) The greatest common factor of x and y is 1
Means numbers are prime. Still sufficient

However, together it can be understood either x or y is 2,to make LCM even and other is odd

IMO c is the answer

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from option 1
we know that HCF*LCM=Product of the two numbers even*even= even even*odd=even not sufficient
from 2 odd+odd=even or odd+ even=odd not sufficient
combining both is sufficient
c
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If x and y are positive integers, is x + y an even integer?


st1) This means the multiplication of 2 integers is even (since LCMxHCF = xy), but that could mean either x & y both are even or one of them is. INSUFFICIENT

st2) LCM = xy (the numbers are co-primes, e.g., x = 3, y = 5 or x = 2, y = 3) INSUFFICIENT

Both taken together, xy = LCM = even , in this case both x & y can't be EVEN because in that case, minimum GCF will be 2. So, One of them is EVEN & the other ODD.

SUFFICIENT

The answer should be C
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x,y=+ve int
is x+y=even?
we know, even+even=even or
odd+odd=even

(1) The product of the greatest common factor of x and y and the least common multiple of x and y is even
take x=2 y=4
gcd=2 & lcm=4..product=2*4=8=even
so both even..x+y=even..yes
take x=2,y=3
gcd=1 & lcm=6..product=6=even
so one even 7 another odd..x+y=odd..no
not sufficient

(2) The greatest common factor of x and y is 1
take x=3 & y=8 gcd=1..x+y=11 odd no
take x=3 & y=5 gcd=1..x+y=8 even yes
not sufficient

combine,
gcd=1 & gcd*lcm=even
so, we cannot take both x,y =odd or even
so we have to take one odd & another even
we know, odd+even=odd no
sufficien..ans C
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If x and y are positive integers, is x + y an even integer?

Pre-thinking: x+y will be even if both intigers are even only or odd only.

Solution:

(1) The product of the greatest common factor of x and y and the least common multiple of x and y is even

Considering statement (1)
Product of gcf and lcm of two numbers is = product of numbers themselves.
Thus, x*y = even integer.
However, product of two integers is even if even one of the integers is even.
Thus, x and y could be 1 and 2 or 4 and 6. Using above samples, x+y could be even or also odd.

As there is no unique answer, statement (1) by itself is not sufficient.

(2) The greatest common factor of x and y is 1

Considering statement (2)
The gcf of x and y can be 1 for only two cases, any integer and 1 also two prime integers.
Thus, x and y could be 1 and 2 or 5 and 7. Using above samples, x+y could be even or also odd.

As there is no unique answer, statement (2) by itself is not sufficient.

Combining statement (1) and statement (2)
If gcf*lcm i.e. x*y= even and gcf=1, x and y can only be 1 and 2 from the samples considered in the two statements individually.
Both statements combined are enough.

Answer should be Option C.

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it's pretty simple we have to figure out the different possiblities '
A- for example let's take 2,3 , gc=1, lcm= 6 , together 2+3= 5 odd n0 , 2,4 , gc= 2 , together 6 even yes ,clearly not suff
B - same examples 2,3= odd , 5,7 ,gc= 1, lcm= 35 , together 12 even clearly each individually is insuff
when combined it;s sufficient for instance it;s odd whenever the gcd is 1 and lcm is even 2,3 or 2,5
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