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1. Analyzing the first statement we can see that X can be either ½ or ¼. Since ½ power of ½ and ¼ power of ¼ both yield (1/2)^(1/2)

So the answer either can be yes and not. So insufficient.

2. The highest common factor of integers 1/x^2 and 1/x^4 is the square of a prime number

from this choice we can see that 1/x can only be ½, 1/3, 1/5, 1/7, and so on. Statements says that 1/x^2 is an integer. For this x must be a fraction whose reversal is a prime number such as 2, 3 , 5, 7 and so on. only in such case 1/x^2 and 1/x^4 can have the square of a PRIME number as the highest common factor. Sufficient.

So B
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Bunuel
If x > 0, is 1/x a prime number ?

(1) \(x^x = \frac{1}{\sqrt{2}}\)

(2) The highest common factor of integers 1/x^2 and 1/x^4 is the square of a prime number


 


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for statement 1 we can take 2
cases 1: (1/2)^1/2 = 1/(2)^1/2 in this case it's prime 1/x is prime

however case 2 : (1/4) ^1/4 =1/(2)^1/2 in this cae 1/x is not prime

clearly insufficient

for statement 2
1/x^2 and 1/x^4 has 1/x^2 as common factor and it explicitly states it's a prime factor squared which implies 1/x is prime clearly sufficient

Therefore IMO B
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Bunuel
If x > 0, is 1/x a prime number ?

(1) \(x^x = \frac{1}{\sqrt{2}}\)

(2) The highest common factor of integers 1/x^2 and 1/x^4 is the square of a prime number



Answer: Option B

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Can someone explain how 1/x ever be a prime number. I thought prime numbers need to be intergers and hence a fraction cannot be prime.
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raju1212
Can someone explain how 1/x ever be a prime number. I thought prime numbers need to be intergers and hence a fraction cannot be prime.


If x is a fraction, then 1/x can be an integer.
For example x=1/2 means 1/x=2
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