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In how many ways can a teacher in a kindergarten school arrange a group of 6 children (Susan, Karen, lei, Tim, joy and Zen) on 6 identical chairs in a straight line so that Susan is on the left of Tim?

A. 720
B. 360
C. 240
D. 120
E. 60

6 children can be arranged in 6! ways. Now, in half of these arrangements Susan will be on the left of Tim and in half she'l be on the right of Tim, so the answer is 6!/2=360.

Answer: B.

Similar questions to practice:
susan-john-daisy-tim-matt-and-kim-need-to-be-seated-in-130743.html
goldenrod-and-no-hope-are-in-a-horse-race-with-6-contestants-82214.html
in-how-many-different-ways-can-the-letters-a-a-b-91460.html

Hi Bunuel,

can you please help me understand how did u come to the conclusion that for half the arrangements S is to the left of T and other half to the right of T?

Regards
Harsha
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harshavmrg
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Vamshi8411
In how many ways can a teacher in a kindergarten school arrange a group of 6 children (Susan, Karen, lei, Tim, joy and Zen) on 6 identical chairs in a straight line so that Susan is on the left of Tim?

A. 720
B. 360
C. 240
D. 120
E. 60

6 children can be arranged in 6! ways. Now, in half of these arrangements Susan will be on the left of Tim and in half she'l be on the right of Tim, so the answer is 6!/2=360.

Answer: B.

Similar questions to practice:
susan-john-daisy-tim-matt-and-kim-need-to-be-seated-in-130743.html
goldenrod-and-no-hope-are-in-a-horse-race-with-6-contestants-82214.html
in-how-many-different-ways-can-the-letters-a-a-b-91460.html

Hi Bunuel,

can you please help me understand how did u come to the conclusion that for half the arrangements S is to the left of T and other half to the right of T?

Regards
Harsha

S and T can have ONLY TWO positions: S to the right of T OR to the left, how else?

Now, why should S be in more cases to the right of T than to the left? Does probability favors either of them? No. Hence exactly in half of these cases S will be to the right of T and in half of these cases to the left.

Check these links for more:
susan-john-daisy-tim-matt-and-kim-need-to-be-seated-in-130743.html
goldenrod-and-no-hope-are-in-a-horse-race-with-6-contestants-82214.html
in-how-many-different-ways-can-the-letters-a-a-b-91460.html
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Vamshi8411
In how many ways can a teacher in a kindergarten school arrange a group of 6 children (Susan, Karen, lei, Tim, joy and Zen) on 6 identical chairs in a straight line so that Susan is on the left of Tim?

A. 720
B. 360
C. 240
D. 120
E. 60

We see that the 6 students can be arranged in 6! = 720 ways. We also can determine that the number of ways in which Susan can be placed to the left of Tim is equal to the number of ways in which she can be placed to the right of Tim. Half the time she is to his right and half the time she is to his left. Thus, the number of ways the teacher can arrange the group with Susan to the left of Tim is 720/2 = 360 ways.

Answer: B
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Note that if we read the question as number of ways where the two children are right next to one another, then the answer becomes 5!. Indeed assuming Tim is the first person to sit, he only has 5 spots, not 6, to choose from - he cannot sit at the far left.
So answer is (6-1)!
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In how many ways can a teacher in a kindergarten school arrange a group of 6 children (Susan, Karen, lei, Tim, joy and Zen) on 6 identical chairs in a straight line so that Susan is on the left of Tim?

Total number of possibilities= 6! = 720

constraints:
We need to arrange 2 chairs for susan and tim so that susan is on the left of tim

Step 1:
Possibility of arranging 2 chairs for Susan and Tim = The possibilities is 6C2 =\(\frac{6!}{2!*4}\)! = 15

Step 2:
Number of arrangement for other 4 children = 4! = 24

Total number of arrangements = 15 * 24 = 360

Ans:B
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