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Difficulty:
65%
(hard)
Question Stats:
55% (02:00) correct
45%
(02:06)
wrong
based on 218
sessions
History
Date
Time
Result
Not Attempted Yet
Two highways start from a point P and meet again at the point Q. Between P and Q there are 5 subways, joining the highways at 5 different places. How many different routes are possible for a journey from P to Q?
(A) 12
(B) 16
(C) 24
(D) 32
(E) 64
not sure, how to work with this kind of problem
(A) 12
(B) 16
(C) 24
(D) 32
(E) 64
not sure, how to work with this kind of problem
Attachments
File comment: Two highways start from a point P and meet again at the point Q
PQ.png [ 4.31 KiB | Viewed 5884 times ]
mynhauzen
No. of ways of using no subways = \(2*5C_0 = 2*1 = 2\)
No. of ways of using one subway = \(2*5C_1 = 2*5 = 10\)
No. of ways of using two subways = \(2*5C_2 = 2*10 = 20\)
No. of ways of using three subways = \(2*5C_3 = 2*10 = 20\)
No. of ways of using four subways = \(2*5C_4 = 2*5 = 10\)
No. of ways of using five subways = \(2*5C_5 = 2*1 = 2\)
We are multiplying by 2 on each occasion because for each combination, we can start the trip either by route 1 or by route 2.
Total = 2 + 10 + 20 + 20 + 10 + 2 = 64
Attachments
untitled.JPG [ 7.67 KiB | Viewed 5769 times ]
If one starts its journey from point P, one has 2 options ( to go via either highway)... When he reaches 1st subway point he has again, 2 options, to continue on the highway or to go through subway., When he reaches next subway, he will have same two options, of course we are considering that he doesn't return from any point.
Since, there are 5 subways, he has the option of choosing from 2 choices 6 times (one when he just starts his journey). So, total ways he can reach is destination is 2^6 = 64.
Since, there are 5 subways, he has the option of choosing from 2 choices 6 times (one when he just starts his journey). So, total ways he can reach is destination is 2^6 = 64.
mynhauzen
This is a poor quality question. In order the answer to be 64, must be mentioned that we should go directly from P to Q without retracing any point along a path, otherwise infinitely many routs will be possible.
In this case, along the path from P to Q we'll have 6 forks and 2 options for each (starting from P), thus there are 2^6=64 routs possible.
Answer: E.
Proper question testing the same concept is here: the-diagram-above-shows-the-various-paths-along-which-a-mous-144271.html
Hope it helps.
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Option E it is .. well explained above !
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