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josemnz83
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josemnz83
For which of the following functions does f(x)=f(2-x)?

A. f(x)=x+2
B. (fx)=2x-x^2
C. f(x)=2-x
D. f(x)=(2-x)^2
E. f(x)=x^2

Answer choice C seems to work out if we plug in 1 for x. Did I do something wrong or must the function be true for all values? C does not work for a value of x=4?
f(x)=2-1=1
f(x)= 2-(2-x).....>2-(2-1).....>2-(1) = 1

If we plug x=0 then, f(0)=f(2)
A. F(0)= 2 and f(2)= 4
B. f(0)= 0 and f(2)= 0
C. F(0)= 2 and f(2)= 0
D. F(0)= 4 and f(2)= 0
E. f(0)= 0 and f(2)= 4

Hence b is the correct answer.
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It can be easily done in less than a minute simply by elimination or substitution method.

1) f(x)=x+2; for x=2-x , f(2-x)=4. Eliminated
2) f(x) = 2x-x^2; for x=2-x ,f(2-x)=2(2-x)-(2-x)^2 =(2-x)(2-2+x)=2x-x^2
3) f(x) = 2 - x; for x=2-x, f(2-x)=x . Eliminated
4) f(x)=(2-x)^2; for x=2-x, f(2-x)=(x)^2 . Eliminated
5) f(x)=x^2;for x=2-x, f(2-x)=(2-x)^2. Eliminated
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What confuses my about this question, with answer "B," is an example in which you have f(2-3)

f(2-3)=-1

F(x)= 2(2-x)-(2-x)^2
F(2-3)= 2(2-3)-(2-3)^2
F(2-3)= 2(-1)-(-1)^2
F(2-3)= -2-1
F(2-3)= -3?

Maybe I'm tired or something but I keep coming to this conclusion.
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Nunuboy1994
What confuses my about this question, with answer "B," is an example in which you have f(2-3)

f(2-3)=-1

F(x)= 2(2-x)-(2-x)^2
F(2-3)= 2(2-3)-(2-3)^2
F(2-3)= 2(-1)-(-1)^2
F(2-3)= -2-1
F(2-3)= -3?

Maybe I'm tired or something but I keep coming to this conclusion.

A good way to solve it is like this. Essentially the question is saying F(X) so everytime you see an X you're going to sub in the function 2-x. A good video explaining how functions work is here since most people here do a crappy job. https://www.youtube.com/watch?v=T6-Zdr5w_bE
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josemnz83
For which of the following functions does f(x)=f(2-x)?

A. f(x)=x+2
B. (fx)=2x-x^2
C. f(x)=2-x
D. f(x)=(2-x)^2
E. f(x)=x^2

Answer choice C seems to work out if we plug in 1 for x. Did I do something wrong or must the function be true for all values? C does not work for a value of x=4?
f(x)=2-1=1
f(x)= 2-(2-x).....>2-(2-1).....>2-(1) = 1


hi

let f(0) = f(2)

B: f(0) = 0
f(2) = 4 - 4 = 0

so f(0)= f(2)
B is the answer

thanks
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josemnz83
For which of the following functions does f(x)=f(2-x)?

A. f(x)=x+2
B. (fx)=2x-x^2
C. f(x)=2-x
D. f(x)=(2-x)^2
E. f(x)=x^2

A. f(x)=x+2
f(2-x) = 2-x+2, Not equal

B. f(x)=2x-x^2
f(2-x) = 2*(2-x) - (2-x)^2 = 4-2x- [ 4 + x^2 - 4x] = 2x-x^2

C. f(x)=2-x
f(2-x) = 2-2+x = x, Not equal

D. f(x)=(2-x)^2
f(2-x)= (2-2-x)^2 , Not equal

E. f(x)=x^2
f(2-x) = (2-x)^2, Not equal

Answer B
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Take a number like x=0, then f(0)=f(2)

Substitute x=0 and x=2 for all the options and they must be equal.
Only option B does that.

___________________

Substituting 1 would give f(1)=f(1) ur comparing two values that will be the same definitely. Hence one must not use 1 here.
josemnz83
For which of the following functions does \(f(x)=f(2-x)\)?

A. \(f(x)=x+2\)

B. \(f(x)=2x-x^2\)

C. \(f(x)=2-x\)

D. \(f(x)=(2-x)^2\)

E. \(f(x)=x^2\)

Answer choice C seems to work out if we plug in 1 for x. Did I do something wrong or must the function be true for all values? C does not work for a value of x=4?
f(x)=2-1=1
f(x)= 2-(2-x).....>2-(2-1).....>2-(1) = 1
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Hi Nunuboy1994,

Your calculation of f(2-3) = f(-1) = -3 is actually perfectly correct! The issue is you stopped halfway — you only computed one side of the equation.

The property f(x) = f(2-x) means: for any x you pick, f(x) and f(2-x) should give the same result.

Let's pick x = 3 and check BOTH sides:

Left side: f(x) = f(3)
f(3) = 2(3) - (3)2 = 6 - 9 = -3

Right side: f(2-x) = f(2-3) = f(-1)
f(-1) = 2(-1) - (-1)2 = -2 - 1 = -3

Both sides equal -3. It works!

You correctly got f(-1) = -3 but never compared it against f(3). Once you compute f(3) = -3 as well, you can see they match perfectly.

Try another pair to build confidence. Let x = 0, so 2-x = 2:

f(0) = 2(0) - (0)2 = 0
f(2) = 2(2) - (2)2 = 4 - 4 = 0

Again, both equal 0. Key Insight: The function is symmetric around x = 1, which is exactly what f(x) = f(2-x) means — the graph is a mirror image on either side of the line x = 1.

Answer: B
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