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Bunuel
Official Solution:

If x is an integer and \(9 \lt x^2 \lt 99\), then what is the value of maximum possible value of \(x\) minus minimum possible value of \(x\)?

A. \(5\)
B. \(6\)
C. \(7\)
D. \(18\)
E. \(20\)


Notice that \(x\) can take positive, as well as negative values to satisfy \(9 \lt x^2 \lt 99\), hence \(x\) can be: -9, -8, -7, -6, -4, 4, 5, 6, 7, 8, or 9. We are asked to find the value of x(max)-x(min), and since x(max)=9 and x(min)=-9 then x(max)-x(min)=9-(-9)=18.


Answer: D

but the questions is asking about x not x^2 though

9 < x^2 < 99

Take the square root of all sides. Now when you take the square root of a number you get a positive and a negative root: √9 = ±3 and √99 ≅ ±9.95. This produces two intervals for x:

-9.95 < x < -3 and 3 < x < 9.95

Since x is an integer, its maximum value is x = 9 and its minimum value is x = -9

(Max Value of x) - (Min Value of x) = 9 - (-9) = 9 + 9 = 18
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Good question.
Need to consider the negative values as well...
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x can take positive, as well as negative values

One should always consider all possible cases in mind.
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I think this is a high-quality question and I agree with explanation. GG. Well Played...
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This is a high-quality and "tricky" question.
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This is a definitely a high quality question and I agree with the explanation.
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Very good, tricky and gmat kind of a question. Sad to see people are judging it as a poor quality question without properly understanding/thinking through the solution :(
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I think this is a high-quality question and I agree with explanation.
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Bunuel


If x is an integer and \(9 \lt x^2 \lt 99\), then what is the value of maximum possible value of \(x\) minus minimum possible value of \(x\)?

A. \(5\)
B. \(6\)
C. \(7\)
D. \(18\)
E. \(20\)


Notice that \(x\) can take positive, as well as negative values to satisfy \(9 \lt x^2 \lt 99\), hence \(x\) can be: -9, -8, -7, -6, -4, 4, 5, 6, 7, 8, or 9. We are asked to find the value of x(max)-x(min), and since x(max)=9 and x(min)=-9 then x(max)-x(min)=9-(-9)=18.

Answer: D


Bunuel: Not sure if I'm misunderstanding, but I thought GMAT's mathematical rules require us to disregard negative roots?
This means that the only acceptable derivation of \(9 < x^2 < 99\) -->\( 3 < x < 9.9...\)
Which makes the maximum minus minimum = 9 - 3 = 6

Ans: B
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Bunuel


If x is an integer and \(9 \lt x^2 \lt 99\), then what is the value of maximum possible value of \(x\) minus minimum possible value of \(x\)?

A. \(5\)
B. \(6\)
C. \(7\)
D. \(18\)
E. \(20\)


Notice that \(x\) can take positive, as well as negative values to satisfy \(9 \lt x^2 \lt 99\), hence \(x\) can be: -9, -8, -7, -6, -4, 4, 5, 6, 7, 8, or 9. We are asked to find the value of x(max)-x(min), and since x(max)=9 and x(min)=-9 then x(max)-x(min)=9-(-9)=18.

Answer: D


Bunuel: Not sure if I'm misunderstanding, but I thought GMAT's mathematical rules require us to disregard negative roots?
This means that the only acceptable derivation of \(9 < x^2 < 99\) -->\( 3 < x < 9.9...\)
Which makes the maximum minus minimum = 9 - 3 = 6

Ans: B

\(\sqrt{nonnegative \ number}\geq 0\) but \(x^2 = 9\) has TWO solutions, +3 and -3. Because \(x^2 = 9\) means that \(x =-\sqrt{9}=-3\) or \(x=\sqrt{9}=3\).
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Bunuel
If x is an integer and \(9 \lt x^2 \lt 99\), then what is the value of maximum possible value of \(x\) minus minimum possible value of \(x\)?

A. \(5\)
B. \(6\)
C. \(7\)
D. \(18\)
E. \(20\)


Hi Bunuel,

I am not sure if I am satisfied with the explanations provided (not saying that the explanations provided here are incorrect, I am sure they are correct).

I feel I still have some gaps in clarity. I found my reasoning to correct answer as the following and please correct me if I am wrong somewhere.

So we arrive at x having the following as the values after taking the square root of all the sides

√9 = ±3 and √99 ≅ ±9.95. This produces two ranges for both sides when considering both sides independently.

-3 > x > 3 and -9.95 < x < 9.95

When we plot these two ranges on a number line then we get a maximum integer value of x = 9 and a minimum value of x = -9

So since the question asked the difference between Max and Min, hence,
(Max Value of x) - (Min Value of x) = 9 - (-9) = 9 + 9 = 18


So I have a couple of questions

1. Is my reasoning and thought process correct?
2. When we are given a question where the variable has a range on both sides like we have in this question, can I consider both sides independently and derive the range and then look at both ranges together on the number line?


Thanks,
Sud
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Sud2021
Bunuel
If x is an integer and \(9 \lt x^2 \lt 99\), then what is the value of maximum possible value of \(x\) minus minimum possible value of \(x\)?

A. \(5\)
B. \(6\)
C. \(7\)
D. \(18\)
E. \(20\)


Hi Bunuel,

I am not sure if I am satisfied with the explanations provided (not saying that the explanations provided here are incorrect, I am sure they are correct).

I feel I still have some gaps in clarity. I found my reasoning to correct answer as the following and please correct me if I am wrong somewhere.

So we arrive at x having the following as the values after taking the square root of all the sides

√9 = ±3 and √99 ≅ ±9.95. This produces two ranges for both sides when considering both sides independently.

-3 > x > 3 and -9.95 < x < 9.95

When we plot these two ranges on a number line then we get a maximum integer value of x = 9 and a minimum value of x = -9

So since the question asked the difference between Max and Min, hence,
(Max Value of x) - (Min Value of x) = 9 - (-9) = 9 + 9 = 18


So I have a couple of questions

1. Is my reasoning and thought process correct?
2. When we are given a question where the variable has a range on both sides like we have in this question, can I consider both sides independently and derive the range and then look at both ranges together on the number line?


Thanks,
Sud

√9 = 3 only and √99 = 9.somethin only! The square root sign CANNOT given negative result.

You could take the square root from \(9 \lt x^2 \lt 99\) and you'd get \(9 \lt |x| \lt 9.something\), hence \(x\) can be: -9, -8, -7, -6, -5, -4, 4, 5, 6, 7, 8, or 9.
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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9 < x^2 < 99
9 < x^2 ≤ 81 (because x is an integer)

Since x is raised to an even exponent, x can be positive or negative.

Possible pos values of x = 4, 5, 6, 7, 8, 9
Possible neg values of x = -4, -5, -6, -7, -8, -9

Max possible value = 9
Min possible value = -9
Difference: 9-(-9) = 18
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I think this is a high-quality question and I agree with explanation.
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