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605-655 (Medium)|   Number Properties|                        
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(1) x could be 1, 4,9,25,36,49..any number ,which is a perfect square. Hence , insufficient.

(2) x could be 1, 12,25... Hence, insufficient

(1) + (2)..x could be 1 giving result 5-1=4 or x could be 25, giving result 7-5=2. Hence, Insufficient.

Answer is E.
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Bunuel
If x is a positive integer, what is the value of \(\sqrt{x+24}-\sqrt{x}\)?

(1) \(\sqrt{x}\) is an integer
(2) \(\sqrt{x+24}\) is an integer

Target question: What is the value of √(x + 24) - √x?

Given: x is a positive integer

Statement 1: √x is an integer
There are several values of x that satisfy statement 1. Here are two:
Case a: x = 1 (notice that √1 is an integer). In this case, √(x + 24) - √x = √(1 + 24) - √1 = 5 - 1 = 4
Case b: x = 4 (notice that √4 is an integer). In this case, √(x + 24) - √x = √(4 + 24) - √4 = √28 - 2
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: √(x + 24) is an integer
There are several values of x that satisfy statement 2. Here are two:
Case a: x = 1 (notice that √(1 + 24) = √25 = 5, which is an integer). In this case, √(x + 24) - √x = √(1 + 24) - √1 = 5 - 1 = 4
Case b: x = 25 (notice that √(25 + 24) = √49 = 7, which is an integer). In this case, √(x + 24) - √x = √(25 + 24) - √25 = 7 - 5 = 2
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Case a: x = 1. In this case, √(x + 24) - √x = √(1 + 24) - √1 = 5 - 1 = 4
Case b: x = 25. In this case, √(x + 24) - √x = √(25 + 24) - √25 = 7 - 5 = 2
Since we cannot answer the target question with certainty, the combined statements are NOT SUFFICIENT

Answer: E
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Statement 1 - Clearly insufficient, x can be any number that is perfect square.
Statement 2- Same explanation as statement 1
Combining both statement-

Let \(\sqrt{x+24}\)=a and \(\sqrt{x}\)=b
x+24=a^2 and x=b^2
a^2-b^2=24
(a+b)(a-b)=24
Possible Solutions
1. a+b=12 and a-b=2
a=7,b=5
2. a+b=6 and a-b=4
a=5 and b=1

Insufficient.


Bunuel
If x is a positive integer, what is the value of \(\sqrt{x+24}-\sqrt{x}\)?

(1) \(\sqrt{x}\) is an integer
(2) \(\sqrt{x+24}\) is an integer
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VeritasKarishma hi!!
Do you find another way to solve this problem?
I mean I found that x could be 1 but not that x could be 25... Do you know any trick to notice that x=1 is not the only option...
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patto
VeritasKarishma hi!!
Do you find another way to solve this problem?
I mean I found that x could be 1 but not that x could be 25... Do you know any trick to notice that x=1 is not the only option...

Knowing that as numbers increase in value, the difference between their perfect squares keeps increasing helps get a small range of values to try.

Also,
1^2 = 1
2^2 = 4 (Diff from above 3)
3^2 = 9 (Diff from above 5)
4^2 = 16 (Diff from above 7)
5^2 = 25
6^2 = 36
7^2 = 49
8^2 = 64
9^2 = 81
10^2 = 100
11^2 = 121 (Diff from above 21)
12^2 = 144 (Diff from above 23)
13^2 = 169 (Diff from above 25)

So difference between 13^2 and any other perfect square will certainly be more than 24.
Hence, we just need to put x equal to these first few values to see when it gives another perfect square when 24 is added to it.

So start with x could be 1 such that x + 24 = 25 (Both perfect squares) - great!
x could be 4 such that x+24 = 28
x could be 9 such that x+24 = 33
x could be 16 such that x+24 = 40
x could be 25 such that x+24 = 49 (Both perfect squares) - great!

Answer (E)
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Bunuel
If x is a positive integer, what is the value of \(\sqrt{x+24}-\sqrt{x}\)?

(1) \(\sqrt{x}\) is an integer
(2) \(\sqrt{x+24}\) is an integer


(1) x can be 1, the answer will be 5-1 =4
x can be 4, the answer be \(\sqrt{4+24}\)-2
So Two different values; Insufficient.

(2) Again x can be 1 the value will 5-1 = 4, but x can also be 12, the answer will be 6-\(\sqrt{12}\)

Two diffierent asnwers.

Insufficient.

Considering both the options.
Applying the same common facts that were considered for option (1) and (2) there are two different answers.

The answer is E.
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If x is a positive integer, what is the value of \(\sqrt{x+24}-\sqrt{x}\)?

(1) \(\sqrt{x}\) is an integer
Can not say. x can be any square value integer
Not sufficient

(2) \(\sqrt{x+24}\) is an integer
Can not say. x can be any square value integer-24
Not sufficient

Both statements together
There are two possibilities.
x=1 or x=25

Not sufficient

E
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Bunuel
If x is a positive integer, what is the value of \(\sqrt{x+24}-\sqrt{x}\)?

(1) \(\sqrt{x}\) is an integer
(2) \(\sqrt{x+24}\) is an integer


Answer: Option E

Video solution by GMATinsight

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This is a value kind of DS question, so we need to find a value for the given expression knowing x is a positive integer.

From statement I alone, we can conclude that x is a perfect square.

If x = 1, value of \(\sqrt{(x+24)}- \sqrt{x}\) = 4

If x = 25, value of \(\sqrt{(x+24)}- \sqrt{x}\) = 2.

Statement I alone is insufficient to find a unique value of the expression. Answer options A and D can be eliminated. Possible answer options are B, C or E.

From statement II alone, \(\sqrt{(x+24)}\) is an integer. This means (x+24) is a perfect square.

We can use the same values to prove that (x+24) is a perfect square and hence the information given in statement II will also be insufficient.
Answer option B can be eliminated. Possible answer options are C or E.

Since statement II does not add anything new to the information given in statement I or further it in any way, the combination of statements is insufficient to find a unique value for the expression. Answer option C can be eliminated.

The correct answer option is E.

Hope that helps!
Aravind B T
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I have a doubt here. Can I say that the numbers could be -7 and -5 also? Or do I have to take the under root of a number to be positive only?
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I have a doubt here. Can I say that the numbers could be -7 and -5 also? Or do I have to take the under root of a number to be positive only?

We are told that "x is a positive integer" so you cannot plug negative numbers. Plus, even roots from negative numbers are undefined on the GMAT.
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Video solution from Quant Reasoning:
Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1
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