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Bunuel
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stat1: cost is not required,, not suff

stat2: if b = 11, a=9
b = 9 , a =11.
not suff

both combined not suff

ans E
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Starting with the easier statement.

Statement 2: b<12 ; In the final mixture of 20 if b is 11, a =9 OR if b=9, a=11.
Clearly a can be more than 10 or less than 10..........Insufficient AD BCE

Statement 1: cost of final mixture is less than 120
We know that a+b=20
5a+7b<120
5a+7(20-a)<120
5a+140-7a<120
-2a<-20
a<10.............Sufficient

Answer is A
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...and 20 pounds of Seed Z contains a pounds of Seed X and b pounds of Seed Y. Is a > 10?

If a = 10, then note that a = b. (to make up 20 pounds together)
So the question also translates to : Is a > b?

If we look at the prices now,
Seed X costs $5 per pound and Seed Y costs $7 per pound
If a = b, then Seed Z price per pound is simply the average of Seed X and Seed Y prices per pound, which is ($5+$7)/2 = $6.

Now,
- If the price of Seed Z per pound is less than $6, we know that there is more of Seed X in the mixture. So a > b.
- If the price of Seed Z per pound is more than $6, we know that there is more of Seed Y in the mixture. So a < b.

Let's look at the 2 statements now..

(1) 20 pounds of Seed Z costs less than $120
It's clear that the price of Seed Z per pound is less than $6. So a > b. This statement in sufficient.

(2) b < 12
We have already established that the question translates to : Is a > b?
Since b < 12 :
- If I take b = 11, then a = 20 - b = 9. So a < b.
- If I take b = 9, then a = 20 - b = 11. So a > b.
This statement is insufficient as we can't establish a clear relationship between a and b.

So the answer is A.
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Bunuel
Seed X costs $5 per pound and Seed Y costs $7 per pound. Seed Z is a blend of the two seeds, and 20 pounds of Seed Z contains a pounds of Seed X and b pounds of Seed Y. Is a > 10?

(1) 20 pounds of Seed Z costs less than $120

(2) b < 12

Quote:
If Seed Z were made of exactly ½ Seed X and ½ Seed Y, then the cost of Seed Z would be $6 per pound (exactly halfway between $5 and $7). So if 20 pounds of Seed Z costs $120 ($6 per pound) then a = 10 and b = 10. Statement 1 tells you that the total of 20 pounds of Seed Z is LESS than $120 so there must be more pounds of Seed X than Seed Y. This means than a must be greater than 10 and statement 1 is sufficient.
Quote:
Statement 2 if b = 11 then a would be 9 and the answer is no to the question. However if b = 4 then a = 16 and the answer is yes. Statement 2 is not sufficient and the answer is A.
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X+Y=20
i.e. ab+b=20

Stmt 1
20 pounds cost less than 120
lets say a =b=10
cost =120
for the total to cost less than 120

logically a needs to be greater than b as a costs less than b

stmt 2 - b can be 11 or 9 so we cant comment on whether a>b or b>a
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Bunuel
Seed X costs $5 per pound and Seed Y costs $7 per pound. Seed Z is a blend of the two seeds, and 20 pounds of Seed Z contains a pounds of Seed X and b pounds of Seed Y. Is a > 10?

(1) 20 pounds of Seed Z costs less than $120

(2) b < 12

20=a+b
z=5a+7b

(1) sufi

z=5a+7b<120, 5(20-b)+7b<120,
2b<20, b<10;
a+b=20, b<10, a>10.

(2) insufic

Ans (A)
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I take way too long per question, but to be honest I am glad that I get to the answer. So again a lot of these mixture problems are all about setting up the equations.

Seed X costs $5 per pound and Seed Y costs $7 per pound. Seed Z is a blend of the two seeds, and 20 pounds of Seed Z contains a pounds of Seed X and b pounds of Seed Y. Is a > 10?

(1) 20 pounds of Seed Z costs less than $120

We know from the stem that X + Y = 20.
This statement tells us that 5X + 7Y < 120
Substitute the first equation into the inequality and we get x >10.
Sufficient.

(2) Y < 12
X + Y = 20
Y = 20 - X
Plug that in to the inequality
X > 8
Insufficient.
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Seed X costs $5 per pound and Seed Y costs $7 per pound. Seed Z is a blend of the two seeds, and 20 pounds of Seed Z contains a pounds of Seed X and b pounds of Seed Y. Is a > 10?

(1) 20 pounds of Seed Z costs less than $120

(2) b < 12

if both the seeds were mixed of same quantity: 20

it will be 100 and 140
average: 120

but because it is given in a that it is less than 120, it is clear one has to be more
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St.1 - can do mentally as well using weighted avgs.
5 and 7 are the price values, now if avg. was right in middle i.e., 6 then it means ratio of a/b = 1:1 i.e., both contributed equally i.e. A=10 and B=10, but st.1 says that avg is less than 6 so means the value is drifting more towards 5 OR in other words, the weights of 5 is more than weights of 7 OR simply A >10 and B<10 hence sufficient.

St.2 - clearly not suff
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