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1. |3x-19|>5-x holds for all values of x.
we can open module:
x>19/3, so 3x - 19 > 5 - x and x > 6 (=18/3) - ok
x=19/3, so 0 > 5 - 19/3 or 0>-4/3 - ок
x<19/3, so - 3x + 19 > 5 - x and 14 > 2x or x < 7 (21/3) - ok
The whole expresion is true


2. There is no value of x for which |2x-10| <4-x holds.
the module is positive, 4 - х will be postivie only for x < 4. We can easaly test value x = 1,2,3 and for x<=0 the module can be opened as -2x+10. From -2x+10 < 4 - x we recieve 6 < x and this contradicts the previous condition.

3. -|5x-23| is negative for all values of x.
it is not mentioned that x must be integer, so for x = 23/5 the expresion will be 0

answer C
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Which of the following is/are true?

I. |3x - 19| > 5 - x holds for all values of x.
II. There is no value of x for which |2x - 10| < 4 - x holds.
III. -|5x - 23| is negative for all values of x.

A. None
B. I only
C. I and II only
D. I and III only
E. I, II and III

Source - Expert's Global

Expert's Global's explanation-

Statement I:
The minimum value for |3x-19| is zero, when x = 19/3 = 6.33.
For x =19/3 = 6.33, |3x-19| > 5-x.
For a greater value of x, e.g. x = 7, |3x-19| > 5-x. For a smaller value of x, e.g. x = 5, |3x-19| > 5-x.
So, for any value of x, |3x-19| > 5-x holds.

Statement II:
The minimum value for |2x-10| is zero, when x = 5.
For x = 5, |2x-10| > 4-x.
For a greater value of x, e.g. x = 6, |2x-10| > 4-x. For a smaller value of x, e.g. x = 4, |2x-10| > 4-x.
So, for no value of x, |2x-10| < 4-x holds.

Statement III:
The least value of -|5x-23] is zero, which is not negative. So -|5x-23] is negative does not hold for all values of x.
Only statements I and II are correct.
Hence, C is the correct answer choice.

Answer video link

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