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Bunuel
In a set of consecutive integers the least number is –23. If the average (arithmetic mean) of the set is 1, what is the greatest value in the set?

A. 27
B. 26
C. 25
D. 24
E. 23

-23 to 23 sum is 0 and we have 47 terms now 24+25 = 49 and we will have 49 terms

avg = 0 + 24 +25/49 = 1

thus largest 25
(C) imo
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Bunuel
In a set of consecutive integers the least number is –23. If the average (arithmetic mean) of the set is 1, what is the greatest value in the set?

A. 27
B. 26
C. 25
D. 24
E. 23

A basic rule of number properties, we know that average of consecutive integers = (First term + Last term)/2. Now relating to the question first term is -23 and average of the set is 1. Putting above values in the formula will give us the answer 25. Therefore the answer is (C).
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Bunuel
In a set of consecutive integers the least number is –23. If the average (arithmetic mean) of the set is 1, what is the greatest value in the set?

A. 27
B. 26
C. 25
D. 24
E. 23
answer is C i use the approach of plug in back i used c 1st as rest smaller or larger number will be eliminated as options are in descending order then total number of variables are 25-(-23)+1 because both terms are included. so total terms are 49 now total sum will be till 23 every thing is eliminated left with only 24+25 whose sum is also 49 and then average will be 1.
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Would be easy by just using the mean formula: \(\frac{Xmin + Xmax}{2}= 1\)

Hence \(\frac{-23 + x}{2} = 1\)

\(x = 25\)

Answer = C
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Bunuel
In a set of consecutive integers the least number is –23. If the average (arithmetic mean) of the set is 1, what is the greatest value in the set?

A. 27
B. 26
C. 25
D. 24
E. 23

The least term is -23

So, the numbers keep on increasing in ascending order , { -23 , -22 , -21...........................}

Now, the result of Numbers from - 23 to 23 will yeild 0 and this average of these 47 terms (Including 0) will be 0


Now, go further and check 24 / 48 Not equal to 1 , 24 + 25/49 = 1 , Thus Answer must be (C) 25
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