We know that numbers are consecutive integers.
For statement 2,
If 5 values out of n are negative than, the remaining values will be equal to or more than 0. Therefore, if the value of n is 5 then P will be negative; otherwise, P will be 0 in all other cases.
For ex. -5, -4, -3, -2, -1 then P IS NEGATIVE.
-5, -4, -3, -2, -1, 0 then P is 0.
-5. -4, -3, -2, -1, 0, 1 Then P is O.
The main problem is that we are not told whether n is 5.
quote="IanStewart"]
raghavrf
If P is the product of n distinct integers, is P<0?
1. n distinct integers are consecutive numbers and their median is 4.5
2. Out of n distinct integers 5 are negative
If the OA is B, there's something wrong with the question. If Statement 1 is true, then either the set contains a small number of consecutive integers, and every value is positive, so their product is positive, or the set is larger and the lower values in the set extend to zero or past zero into negative values. But if it's a set of consecutive integers, then the set would then contain zero, so the product of the values in the set would be zero. The product could never be negative, so Statement 1 is sufficient to give a "no" answer to the question.
Statement 2 is not sufficient, because if we have five negative values, and the rest of the values are positive, the product is negative, but if we have five negative values and we have zero in the set, the product is zero. So we can't be sure if the product is negative.[/quote]