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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another 10 Dec 2020, 07:45
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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another contains copper, tin and lead in the ratio 5:4:3. If equal weights of both alloys are melted together to form a third alloy, then the weight of lead per kg in new alloy will be:

A. 1/10 kg
B. 1/8 kg
C. 1/6 kg
D. 1/4 kg
E. 1/2 kg
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B
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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another 10 Dec 2020, 08:56
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Ans is 1 / 8 as if we mix in equal proportions the % becomes half of combined both

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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another 19 Dec 2020, 03:21
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2+3+1=6 -> 2*6=12
5+4+3=12
In order to have both alloys in same proportion, we need 2 kgs of 1st for every 1kg of 2nd:

Proportion of Lead = (0+3)/(2*6+12)= 3/24= 1/8 => C
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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another 19 Dec 2020, 03:53
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Lets take the LCM of 5, 4, 3, 2, 1 = 60
We can assume that 60 kg of each alloy is mixed to form a new alloy

Weights of elements in Alloy1
Z:C:T = 2:3:1
Weights will be:

Z = 20
C = 30
T = 10

Weights of elements in Alloy2
C:T:L = 5:4:3
Weights will be:

C = 25
T = 20
L = 15

Weight of Lead in alloy3 is 15 and total weight is 120 (60+60)
Weight of lead in per kg of alloy3 = 15/120 = 1/8

Option B
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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another Updated on: 05 Jun 2024, 05:19
Originally posted by CrackverbalGMAT on 19 Dec 2020, 05:56.
Last edited by CrackverbalGMAT on 05 Jun 2024, 05:19, edited 1 time in total.
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SOLUTION:
Refer to the figure attached.
Convert the ratios of the first alloy into 4:6:2 so that the quantities of the alloys are made equal(12 units each).

Thus weight of lead = 3/(12+12) = 3/24 =1/8 kg (Option B)

Hope this helps :thumbsup:
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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another 19 Dec 2020, 07:05
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Quote:
An alloy contains zinc, copper and tin in the ratio 2:3:1 and another contains copper, tin and lead in the ratio 5:4:3. If equal weights of both alloys are melted together to form a third alloy, then the weight of lead per kg in new alloy will be:
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First alloy consists of zinc = 2x, copper = 3x, tin = x, Total = 6x
second alloy consists of: copper = 5y, tin = 4y, led = 3y, total = 12y

as amounts of the two alloys are equal; 6x = 12y
x = 2y

Total amount of third alloy produced = 6x + 12y = 24y [as x = 2y]

Fraction of led out of the total amount produced = 3y/24y = 1/8

B is correct
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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another 07 May 2022, 05:21
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Deepakjhamb
Ans is 1 / 8 as if we mix in equal proportions the % becomes half of combined both

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Deepakjhamb
Can You explain from where are you getting this?
Also why aren't we adding the weight of Lead from both the alloys as 3+2=5/24
I am getting 1/6 as the answer

Thank You
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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another 08 Feb 2024, 17:25
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