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RenB
Joined: 13 Jul 2022
Last visit: 06 Jul 2026
Posts: 388
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Location: India
Concentration: Finance, Nonprofit
Schools: Stanford '26 Wharton '26 (D) Booth '26 (D) Yale '26 (D) CBS '26 (A$$$) Darden '26 (WL) HBS '26 (D) Ross '26 (A$$$$) LBS '26 (D) Tuck '26 (A$$) Kellogg '26 (A)
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WE:Corporate Finance (Consulting)
Schools: Stanford '26 Wharton '26 (D) Booth '26 (D) Yale '26 (D) CBS '26 (A$$$) Darden '26 (WL) HBS '26 (D) Ross '26 (A$$$$) LBS '26 (D) Tuck '26 (A$$) Kellogg '26 (A)
GMAT Focus 1: 715 Q90 V84 DI82
Posts: 388
19 Aug 2023, 01:00
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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34% (02:46) correct
66%
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wrong
based on 194
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A bag contains four types of coins: 5-cent coins, 10 cent coins, 50-cent coins, and 1-dollar coins. If the total amount of money in the bag is $16.50 and the total number of coins in the bag is 40, how many 10 cent coins are there? ($1 = 100 cents)
(1) The number of 10 cent coins is equal to the number of 50-cent coins.
(2) The number of 5-cent and 50-cents coins is 10 each.
(1) The number of 10 cent coins is equal to the number of 50-cent coins.
(2) The number of 5-cent and 50-cents coins is 10 each.
19 Aug 2023, 02:20
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RenB
The crux of the question is that the number of coins is an integer and has a value greater than zero.
Attachment:
Screenshot 2023-08-19 144933.jpg [ 135.58 KiB | Viewed 5635 times ]
19 Aug 2023, 02:28
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Option1: x+y+z+a = 40
0.05x + 0.1y+ 0.5z + a = 16.5
y=z
Final equation:
x + 12z + 20a = 330
x + 2z + a = 40
Solving above equations:
10z + 19a = 290
z and a will be 10.
So Option A is sufficient
Posted from my mobile device
0.05x + 0.1y+ 0.5z + a = 16.5
y=z
Final equation:
x + 12z + 20a = 330
x + 2z + a = 40
Solving above equations:
10z + 19a = 290
z and a will be 10.
So Option A is sufficient
Posted from my mobile device
10 Jun 2024, 03:33
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