x is an
absolute value used as a threshold to decide whether an absolute difference in percentages is significant or insignificant, which means
1) We’re trying to find the
min value of x,
beyond which the difference is
significant2) This also means we’re trying to find the
max value of x,
below which the difference is i
nsignificantFor the first part, look for values where difference of rounded off values is
min but was still considered
significant.
This is row 5, column 2014-2015 where values are a = 83 & b = 84, this implies actual values of
82.5 =< a < 83.5
83.5 =< b < 84.5
To get the min of x, subtract max a from min b (since we’re dealing with absolute values, we’re subtracting smaller numbers from bigger numbers throughout)
To get the max of x, subtract min a from max b
Therefore 0 < x < 2 ( important to note, x is not 0 and not 2)
For the second part, look for values where difference of rounded off values is
max but was still considered
insignificant.
This is row 2, column 2014-2015 where values are c = 69 & d = 70, this implies actual values of
68.5 =< c < 69.5
69.5 =< d < 70.5
To get the min of x, subtract max c from min d
To get the max of x, subtract min c from max d
Therefore 0 < x < 2 ( important to note, x is not 0 and not 2)
From both these statements, we arrive at the conclusion that x could be a value
strictly greater than 0 and
strictly less than 2.
Now looking at answers, any option that lies in this range could be x and satisfy all data points in the table. Answer is Y, Y, N.
Additional explanation:
We cannot narrow down further based on the data given in the table. The only reason we checked for the second condition above is to find whether we can narrow down our range from the first condition (for example if d = 71 instead of 70 then 1 < x < 3 which combined with first would have given us 1 < x < 2).
We could have also skipped calculations for step 2, because the difference in rounded off values that are considered significant and insignificant are the same they would yield the same range of 0 to 2 (both not included).
A quick shortcut here is since values are rounded off within a range of 1 unit (slightly less than 1), we directly obtain the range by adding and subtracting 1 from the difference of rounded off values. Just be careful here to note that both extreme values are not included since range is slightly less than 1. If you are uncomfortable with this shortcut, above steps will always result in correct ranges.
To help understand the solution better, let’s assume a really small value of x and check for the above two data points. If it can satisfy these two it will satisfy any other data point.
For example Say x = 0.001, then possible values of a = 83.49, b = 83.5 meaning difference = 0.01 > x
And also c = 69.4999 and d = 69.5 meaning difference = 0.0001 < x
Even though you might consider a difference of 0.001 insignificant, we have no information on whether the author considers it significant or insignificant. We also have no information on the specific actual values so they could be anything within their own ranges that satisfy all the conditions. Therefore all values of 0 < x < 2 could be possible answers.
Here’s another example from the answer options, x = 1.4
Then possible values of a = 82.52, b = 84.13 meaning difference = 1.61 > x
and also c = 68.5 and d = 69.69 meaning difference = 1.19 < x