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When it operates at its own constant rate, hose A can fill an empty tank twice as fast as hose B can when it operates at its own constant rate. If hose A can fill the tank in x hours, how many hours will it take for the two hoses, operating simultaneously, to fill the tank?
A. 2x/3
B. 3x/2
C. 3x
D. 3/(2x)
E. 3/x
A. 2x/3
B. 3x/2
C. 3x
D. 3/(2x)
E. 3/x
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27 Apr 2024, 01:39
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Danou
Given that hose A can fill the tank in x hours, hose B would take 2x hours to fill the tank. Thus, their combined rate is 1/x + 1/(2x) = 3/(2x). Since time is the reciprocal of rate, the two hoses operating simultaneously will take 2x/3 hours.
Answer: A.
P.S. Can you please tell me the exact source of this question? Thank you.
General Discussion
27 Apr 2024, 03:47
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Danou
Lets say Total 120 units
A fills in x hours
Speed of A= 12/x unit/hour
B fills in x/2 hours
Speed of B= 120*2/x= 240/x unit/ hour
Together Speed= 120/x+ 240/x= 360/x
Work= 120
Time= Work/Rate
120/ (360/x)= 120*x/360= 2x/3
A
